AC代码(Python) 1__author__='YE'23#Definition for singly-linked list.4classListNode(object):5def__init__(self, x):6self.val =x7self.next =None89classSolution(object):10defrotateRight(self, head, k):11"""12:type head: ListNode13:type k: int14:rtype: ListNode15"""16ifk == 0or...
https://leetcode.com/problems/rotate-list/ 题意分析: 给定一个链表和一个整型k,在链表从右开始数k处开始旋转这个链表。 题目思路: 首先要确定k是在那个地方,然后开始进行链表操作就可以了。要注意的是k有可能比链表长度要长,要将k mod 链表的长度。 代码(python): View Code 转载请注明出处:http://www....
代码(Python3) class Solution: def rotate(self, nums: List[int], k: int) -> None: """ Do not return anything, modify nums in-place instead. """ n: int = len(nums) # 计算最后有多少数字会被移动到数组开始 k %= n # 翻转整个数组 Solution.reverse(nums, 0, n - 1) # 翻转前 ...
LeetCode 61. Rotate List c++ 题目c++ /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* rotateRight(ListNode* head, int k) { if(he ShenduCC 2019/...
[Leetcode][python]Rotate Image/旋转图像 题目大意 顺时针翻转数组(以图像存储为例) 解题思路 先镜像反转,再每行前后翻转 代码 class Solution(object): def rotate(self, matrix): """ :type matrix: List[List[int]] :rtype: void Do not return anything, modify matrix in-place instead....
【LeetCode】796. Rotate String 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/rotate-string/description/...
Can you solve this real interview question? Search in Rotated Sorted Array - There is an integer array nums sorted in ascending order (with distinct values). Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1
class Solution: def rotate(self, matrix): """ :type matrix: List[List[int]] :rtype: void Do not return anything, modify matrix in-place instead. """ m = len(matrix) n = len(matrix[0]) for i in range(m): for j in range(i + 1): self.swap(matrix, i, j, j, i) for...
*/classSolution{publicListNoderotateRight(ListNode head,int k){if(head==null||head.next==null)returnhead;ListNode dummy=newListNode(0);dummy.next=head;ListNode fast=dummy,slow=dummy;int len;// get list len;for(len=0;fast.next!=null;len++)fast=fast.next;// find rotate nodefor(int i=...
Testcase Test Result Test Result Case 1Case 2 matrix = [[1,2,3],[4,5,6],[7,8,9]] 9 1 2 › [[1,2,3],[4,5,6],[7,8,9]] [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]] Source