LeetCode第[48]题(Java):Rotate Image 题目:矩阵旋转 难度:Medium 题目内容: You are given annxn2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Note: You have to rotate the imagein-place, which means you have to modify the input 2D matrix directly. DO NOT alloca...
Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? 题解: 这道题就是考察很直白的旋转坐标。要in place的。画个图自己算算就出来了。 代码如下: 1/*public void rotate(int[][] matrix) { 2int m = matrix.length; 3int n = matrix[0].length; 4 5int[][...
Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? 交换法 复杂度 时间O(NN) 空间 O(1) 思路 为了Inplace实现这题,我们要用交换的方法,顺序是左上先和左下交换,然后左上和右下交换,然后左上和右上交换。和Spiral Matrix类似,我们通过圈数来控制内外的顺序。 代码 p...
LeetCode Top 100 Liked Questions 48. Rotate Image (Java版; Medium) 题目描述 You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Note: You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. ...
Leecode 第48题,旋转图片。原题链接 https://leetcode.com/problems/rotate-image/Leetcode系列github repo: https://github.com/willyii/LeetcodeRecord, 视频播放量 143、弹幕量 0、点赞数 4、投硬币枚数 4、收藏人数 1、转发人数 0, 视频作者 乱码打死老师傅, 作者简介
LeetCode 48. Rotate Image n x n Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? class Solution { public: void rotate(vector<vector<int>>& matrix) { int length = matrix[0].size(); for(int i = 0; i < length / 2; i ++){...
leetcode python3 leetcode-python rotate-image implementations Updated Jul 1, 2024 Python muiz6 / react-sticker Star 1 Code Issues Pull requests Example to guide on how to create rotatable stickers in React. react nextjs maths sticker rotate-image Updated Jun 27, 2024 JavaScript jk-kel...
给定一个 *n *×n的二维矩阵表示一个图像。 将图像顺时针旋转 90 度。 说明: 你必须在原地旋转图像,这意味着你需要直接修改输入的二维矩阵。请不要使用另一个矩阵来旋转图像。 示例: 给定matrix= [ [1,2,3], [4,5,6], [7,8,9] ],
http://www.programcreek.com/2013/01/leetcode-rotate-image-java/ Anyway, Good luck, Richardo! My code: publicclassSolution{publicvoidrotate(int[][]matrix){if(matrix==null||matrix.length==0||matrix[0].length==0){return;}// swap top with bottominttop=0;intbottom=matrix.length-1;while(...
!谢谢大家了! 分享1赞 leetcode吧 chipgenius Search in Rotated SortedArray直接一遍也可以通过 分享1赞 sdl吧 kkk2ooo1 我想写一个旋转图片的代码,但是旋转的时候会出问题// 因为旋转后的rotatedRobot比原始robot的surface要大,所以有了下面的代码重新确定在screen上位置,但是执行还是有问题,请高手帮帮忙指点...