LeetCode第48题:Rotate Image的解题思路是什么? 在LeetCode 48题中,如何实现图像的顺时针旋转90度? Problem 代码语言:javascript 代码运行次数:0 运行 AI代码解释 # You are given an n x n 2D matrix representing an image. # # Rotate the image by 90 degrees (clockwise). # # Note: # You have ...
solution: voidrotate(int** matrix,intmatrixRowSize,intmatrixColSize){inti,j;inttmp[matrixRowSize][matrixColSize];intused[matrixRowSize][matrixColSize];memset(tmp,0,sizeof(tmp));memset(used,0,sizeof(used));for(i=0;i<matrixRowSize;i++) {for(j=0;j<matrixColSize;j++) {if(used[matr...
LeetCode-Rotate Image You are given annxn2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? classSolution { public: voidrotate(vector<vector<int> > &matrix) { // Start typing your C/C++ solution below // DO NOT write ...
Can you solve this real interview question? Rotate Image - You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise). You have to rotate the image in-place [https://en.wikipedia.org/wiki/In-place_algorithm], whic
LeetCode Rotate Image LeetCode解题之Rotate Image 原题 将一个矩阵顺时针旋转90度。 注意点: 最好不要申请额外空间 样例: 输入: matrix = [[1, 2, 3], [8, 9, 4], [7, 6, 5]] 输出: [[7, 8, 1], [6, 9, 2], [5, 4, 3]]...
运行 AI代码解释 classSolution{public:voidrotate(vector<vector<int>>&matrix){if(matrix.size()<=0)return;int a=0,b=matrix.size()-1;while(a<b){for(int i=0;i<b-a;++i){swap(matrix[a][a+i],matrix[a+i][b]);swap(matrix[a][a+i],matrix[b][b-i]);swap(matrix[a][a+i],mat...
4. two for loop to go through the image. Code: classSolution:defrotate(self, matrix: List[List[int]]) ->None:"""Do not return anything, modify matrix in-place instead."""visited, n=set(), len(matrix)foriinrange(n):forjinrange(n):if(i, j)notinvisited: ...
1. Description Rotate Image 2. Solution Version 1 class Solution{public:voidrotate(vector<vector<int>>&matrix){intn=matrix.size();for(inti=0;i<n;i++){for(intj=i+1;j<n;j++){swap(matrix[i][j],matrix[j][i]);}}for(intk=0;k<n;k++){inti=0;intj=n-1;while(i<j){swap(matr...
classSolution{public:voidrotate(vector<vector<int>>&matrix){reverse(matrix.begin(),matrix.end());for(inti=0;i<matrix[0].size();++i){for(intj=0;j<matrix[0].size();++j){if(i>=j)continue;swap(matrix[i][j],matrix[j][i]);}}}; 总结...
Breadcrumbs leetcode /48.rotate_image / solution.md Latest commit Cannot retrieve latest commit at this time. HistoryHistory File metadata and controls Preview Code Blame 32 lines (20 loc) · 1.3 KB Raw Solutionrotate我們可以透過以下步驟完成 90 度的轉換先用變數 temp 儲存左下角的數字 15...