给定数组,假定value=数组相邻元素两两之差(绝对值)的总和。 允许对数组内某一个连续子数组进行整体反转,使得value能取得最大。求这样的value。 Example 1: Input: nums = [2,3,1,5,4] Output: 10 Explanation: By reversing the subarray [3,1,5] the array becomes [2,5,1,3,4] whose value is 1...
如果两线段无重复,必增加原先的值,且diff为2 * gap。 可通过如下的图进行分类讨论。 最后,再对边界做一个处理即可。 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 intinf = (int)1e9; publicintmaxValueAfterReverse(int[] nums) { intres = 0; i...
数学-绝对值-Reverse Subarray To Maximize Array Value,2020-02-11 12:01:21问题描述:问题求解:本题的难度个人感觉还是蛮大的,主要是不容易想到O(n)的解。对于...a,[b,...,c],d,...,如果我们将其中的[b,...,c]进行翻转。如果两线段有重复,必减小原先的值。如果两线段
publicbooleancanTransform(Stringstart,Stringend){intn=start.length();List<int[]>s=newArrayList<>();List<int[]>e=newArrayList<>();for(inti=0;i<n;i++){charc=start.charAt(i);if(c=='L'||c=='R'){s.add(newint[]{c-'a',i});}c=end.charAt(i);if(c=='L'||c=='R'){e.a...
Write a program to reverse an array or string in C++ Array reverse() vs reverse! in Ruby Write a program to reverse an array in JavaScript? How do I reverse an int array in Java Write a Golang program to reverse an array Reverse Subarray To Maximize Array Value in C++ C Program to ...
2259 Remove Digit From Number to Maximize Result Python 291st Weekly Contest 53 Maximum Subarray Python 54 Spiral Matrix Python 228 Summary Ranges Python 263 Ugly Number Python 203 Remove Linked List Elements Linked List Python 內含Linked List remove 操作 part 2 (for 新手教學) 206 Reverse ...
0915-Partition-Array-into-Disjoint-Intervals 0916-Word-Subsets 0917-Reverse-Only-Letters/cpp-0917 CMakeLists.txt main.cpp main2.cpp 0918-Maximum-Sum-Circular-Subarray 0919-Complete-Binary-Tree-Inserter 0920-Number-of-Music-Playlists 0921-Minimum-Add-to-Make-Parentheses-Vali...
D_Maximize_the_Root.exe D_Maximum_Subarray.cpp D_Med_imize.cpp D_Megalomania.cpp D_Merge_Slimes.cpp D_Minimum_maximum_on_the_Path.cpp D_Mouse_Hunt.cpp D_Nearest_Excluded_Points.cpp D_Non_square_Equation.cpp D_Office_Keys.cpp D_Omkar_and_Bed_Wars.cpp D_Ones_and_Twos.cpp D_Paint_...
publicintmaxValueAfterReverse(int[] nums) { intres = 0; intn = nums.length; intdiff = 0; for(inti = 0; i < n - 1; i++) res += Math.abs(nums[i + 1] - nums[i]); // 端点不在两顶点 intmin = inf; intmax = -inf; ...
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 publicboolean canTransform(String start, String end) { intn = start.length(); List<int[]> s =newArrayList<>(); List<int[]> e =newArrayList<>(); for(inti = 0; i < n; i++) { ...