请使用一趟扫描完成反转。 说明: 1 ≤ m ≤ n ≤ 链表长度。 示例: 输入: 1->2->3->4->5->NULL, m = 2, n = 4 输出: 1->4->3->2->5->NULL 分析 给定初始链表为 1->2->3->4->5->NULL,如图 初始状态 我们需要找到第m个节点和第n个节点,分别记为MNode和 ** NNode** 同时也要...
一个需要再借助一个函数,按照非递归版重写的;另一个比较tricky不需要额外函数。 Reverse Linked List - LeetCode https://leetcode.com/problems/reverse-linked-list/solution/ View Code
在LeetCode论坛发现了一个8ms的解法,不得不为其简洁高效合彩!具体程序如下: 1ListNode* reverseList(ListNode*head) {2ListNode *curr = head, *prev =nullptr;3while(curr) {4auto next = curr->next;5curr->next =prev;6prev = curr, curr =next;7}8returnprev;9} 2. Reverse Linked List II 题目...
https://leetcode.com/problems/reverse-linked-list/ 题目: Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 思路: 头插法建立链表 算法: 1. public ListNode reverseList(ListNode head) { 2. ListNode p = head, q, t...
recursive 解法: 总结是传给helper method两个节点,cur和pre(最开始是head和null), 先用n1存当前节点的next,然后把当前节点的next指向pre,然后一直recursively call help method直到过完整个linkedlist. /** * Definition for singly-linked list. * public class ListNode { ...
问题链接英文网站:92. Reverse Linked List II中文网站:92. 反转链表 II问题描述Given the head of a singly linked list and two integers left and right where left <= right, reverse the nodes of the l…
leetcode 206. Reverse Linked List 反转字符串,Reverseasinglylinkedlist.反转链表,我这里是采用头插法来实现反转链表。代码如下:/*classListNode{intval;ListNodenext;ListNode(intx){val=x;}}*/publicclassSolution{publicListNoderever
LeetCode Reverse a singly linked list. Example: Input:1->2->3->4->5->NULL Output:5->4->3->2->1->NULL Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both? 问题 力扣 反转一个单链表。
LeetCode 206. 反转链表(Reverse Linked List) 示例: 输入:1->2->3->4->5->NULL输出:5->4->3->2->1->NULL 切题 一、Clarification 只需注意为空链表的情况 二、Possible Solution 1、迭代 2、递归 可利用哨兵简化实现难度 Python3 实现
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/add Reverse Linked List II.drawio at b141f1237c763e642d01fc8936d2ebb768c31966 · brianchiang-tw/leetcode