}ListNodep=reverseList(head.next); head.next.next = head; head.next =null;returnp; } } Python 实现 # Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = NoneclassSolution:defreverseList(self, head):""" :type head: ListNode :...
1 #include <iostream> 2 #include <malloc.h> 3 using namespace std; 4 5 struct ListNode { 6 int val; 7 ListNode *next; 8 ListNode(int x) : val(x), next(NULL) {} 9 }; 10 /*在链表的末端插入新的节点,建立链表*/ 11 ListNode *CreateList(int n) 12 { 13 ListNode *head; 14 L...
(参考视频讲解:Leetcode力扣|206反转链表|递归|reverse linked list_哔哩哔哩_bilibili) # 定义一个链表节点类classListNode:def__init__(self,val=0,next=None):# 初始化函数self.val=val# 节点的值self.next=next# 指向下一个节点的指针# 将给出的数组转换为链表deflinkedlist(list):head=ListNode(list[0]...
. - 力扣(LeetCode)leetcode.cn/problems/reverse-linked-list-ii/description/ 解题方法 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode() {} * ListNode(int val) { this.val = val; } * ListNode(int val, ListNode next) {...
def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点 head.next = dummy # dummy.next是Null,所以这样head.next就成为了Null ...
public ListNode reverseList(ListNode head) { ListNode prev = null; ListNode curr = head; while (curr != null) { ListNode nextTemp = curr.next; curr.next = prev; prev = curr; curr = nextTemp; } return prev; }递归逆置单链表 递归法的思路是这样的:把链表看成两部分,当前表头结点head和剩...
力扣LeetCode中文版,码不停题 -全球极客编程职业成长社区 🎁 每日任务|力扣 App|百万题解|企业题库|全球周赛|轻松同步,使用已有积分换礼 × Problem List Problem List RegisterorSign in Premium Testcase Test Result Test Result Given theheadof a singly linked list, reverse the list, and returnthe r...
Leetcode 92题反转链表 II(Reverse Linked List II) LeetCode 206题 反转链表(Reverse Linked List) 题目链接 https://leetcode-cn.com/problems/reverse-linked-list-ii/ 题目描述 反转从位置 m 到 n 的链表。请使用一趟扫描完成反转。 说明: 1 ≤ m ≤ n ≤ 链表长度。 示例: 输入: 1->2->3->4-...
LeetCode.jpg 目录链接:https://www.jianshu.com/p/9c0ada9e0ede 反转一个单链表 LeetCode 206. 反转链表(Reverse Linked List) 示例: 输入:1->2->3->4->5->NULL输出:5->4->3->2->1->NULL 切题 一、Clarification 只需注意为空链表的情况 ...
def reverseList2(self, head: ListNode) -> ListNode: """ 双指针法 :param head: :return: """ # 空表时直接返空 if head is None: return None # 初始化cur为head cur = head while head.next != None: # 当head的next非空时, 完成局部反转 ...