我们接下来要做的是,先把Mpre的next域指向NodeM节点的后一个节点; 再把NodeM所在节点移动到NodeN所在节点之后,使得NodeN的next域指向NodeM所在节点,NodeM所在节点next域指向NodeN的next域所指节点; 然后让NodeM指向Mpre的next域指向的节点; 演示图2 然后再重复上面的步骤; 这是NodeM和NodeN相遇,反转完成。
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given1->2->3->4->5->NULL, m = 2 and n = 4,return1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition:1 ≤ m ≤ n ≤ length of list. Analysis: 这道题还是...
【LeetCode】92. Reverse Linked List II Reverse Linked List II Reverse a linked list from positionmton. Do it in-place and in one-pass. For example: Given1->2->3->4->5->NULL,m= 2 andn= 4, return1->4->3->2->5->NULL. Note: Givenm,nsatisfy the following condition: 1≤m≤...
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1≤ m ≤ n ≤ length of list. 这道题很简单,但...
LeetCode: 92. Reverse Linked List II 题目描述 Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, ...
问题链接英文网站:92. Reverse Linked List II中文网站:92. 反转链表 II问题描述Given the head of a singly linked list and two integers left and right where left <= right, reverse the nodes of the l…
2.每次当newHead = reverseList(head.next)执行完返回时,可以认为head.next所在的节点(假设该节点为A)以及它右边的节点就已经反转好了,所以现在需要处理head和A之间的反转,即要把A指向head,然后head指向None。所以A.next = head,但是这个A节点怎么获取呢,其实A就是head.next,也就是head.next(A).next = head...
反转从位置 m 到 n 的链表。请使用一趟扫描完成反转。 说明: 1 ≤ m ≤ n ≤ 链表长度。 示例: 输入: 1->2->3->4->5->NULL, m = 2, ...
方法2. 3指针public ListNode reverseBetween(ListNode head, int m, int n) { ListNode fakeHead = new ListNode(0); ListNode cur =fakeHead; ListNode curH = head; int cnt = n - m + 1; //链接1到m - 1节点while(m > 1){ cur.next = curH; curH = curH.next; cur = cur.next; m...
Leetcode 92. Reverse Linked List II 题目Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: ......