} Remove Duplicates from Sorted Array II (Java) For example, given sorted array A = [1,1,1,2,2,3], your function should return length = 5, and A is now [1,1,2,2,3]. 最多允许两个重复,输出结果数组。 解法1:当counter是2时,就直接跳过即可,否则说明元素出现次数没有超,继续放入结果...
https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/ 用一个cnt记录不重复的部分,后面每遇到不重复的cnt++即可。 classSolution {public:intremoveDuplicates(intA[],intn) {if(n==0)return0;intlast=A[0]-1;intcount=1;for(inti=0;i<n;i++){if(A[count-1]!=A[i]) { A[cou...
- LeetCodeleetcode.com/problems/remove-duplicates-from-sorted-array/description/ 解题思路 双指针 class Solution { public: int removeDuplicates(vector<int>& nums) { if(nums.size() == 0) return 0; int i = 0, j = 1; while(j < nums.size()) { if(nums[i] != nums[j]) { i+...
题目链接:https://leetcode.com/problems/remove-duplicates-from-sorted-array/ 题目: once Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array nums =[1,1,2],2, with the first two elements of nums being1and2 思路: ...
题目链接:https://leetcode.com/problems/remove-duplicates-from-sorted-list-ii/ 题目: distinct For example, Given1->2->3->3->4->4->5, return1->2->5. Given1->1->1->2->3, return2->3. 思路: 思路很简单,唯一要注意的是 删除操作加入头结点可以减少很多判断。
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this by modifyi…
Can you solve this real interview question? Remove Duplicates from Sorted List II - Given the head of a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. Return the linked list sorted
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
26. 删除有序数组中的重复项 - 给你一个 非严格递增排列 的数组 nums ,请你 原地 [http://baike.baidu.com/item/%E5%8E%9F%E5%9C%B0%E7%AE%97%E6%B3%95] 删除重复出现的元素,使每个元素 只出现一次 ,返回删除后数组的新长度。元素的 相对顺序 应该保持 一致 。然后返回 n
unique巧解 Jeremy_LeeL1发布于 2020-03-243.2kC++ 解题思路 这题其实可以直接用c++自带的unique函数,只要一行代码 代码 class Solution { public: int removeDuplicates(vector<int>& nums) { return unique(nums.begin(),nums.end())-nums.begin(); } }; ...