代码(Python3) class Solution: def removeDuplicateLetters(self, s: str) -> str: # last_index[ch] 表示 ch 在 s 中的最后一个出现的位置 last_index: Dict[str, int] = { # 带下标遍历 s 中的字符,更新每个字符最后一次出现的位置 ch: i for i, ch in enumerate(s) } # is_in_stack[ch]...
穷举思路,只要出现过两次,就将该元素忽略。其实因为数组是有序的,穷举效率肯定差一点,但是leetcode OJ通过了= = AC代码(Python) classSolution(object):defremoveDuplicates(self, nums):""":type nums: List[int] :rtype: int"""k=0 l=len(nums)ifl ==0:return0foriinrange(l): t=0;forjinrange(k...
AC代码(Python) 1#Definition for singly-linked list.2#class ListNode(object):3#def __init__(self, x):4#self.val = x5#self.next = None67classSolution(object):8defdeleteDuplicates(self, head):9"""10:type head: ListNode11:rtype: ListNode12"""13ifhead == Noneorhead.next ==None:14re...
Remove Duplicates from Sorted ArrayTotal Accepted:66627Total Submissions:212739My Submissions Given a sorted array, remove the duplicates in place such that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this in plac...
【摘要】 Leetcode 26 Remove Duplicates 题目描述 Remove Duplicates from Sorted Array Given a sorted array, remove ... Leetcode 26 Remove Duplicates 题目描述 Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return...
Python版本 classSolution(object):defremoveDuplicates(self,nums):""":type nums:List[int]:rtype:int""" length=len(nums)iflength<=2:returnlength #i代表的是increasement,逐渐增加的,insert_pos是逐个插入的 insert_pos=2i=2whilei<length:#当前元素和之前的两个元素都相同的情况下就跳过ifnums[insert_po...
本题和上一篇文章Remove Duplicates from Sorted Array类似,用一个变量存储其他元素的个数count,每遇见一个不等于val的元素,将其赋值给数组第count个位置处,并且count加1,最后返回count即可。 【代码】 python版本 代码语言:javascript 代码运行次数:0 运行 ...
Remove Duplicates系列笔记 第一题 Python代码: # Definition for singly-linked list. classListNode(object): def__init__(self,x): self.val=x self.next=None classSolution(object): defdeleteDuplicates(self,head): """ :type head: ListNode
Python3: 代码语言:txt AI代码解释 class Solution: def removeElement(self, nums: List[int], val: int) -> int: i=0 j=len(nums)-1 while i<=j: if(nums[i]==val): nums[i]=nums[j] j-=1 else:i+=1 return j+1 总结: 代码语言:txt ...
26.remove-duplicates-from-sorted-array.md Breadcrumbs leetcode /problems / 题目地址(26. 删除排序数组中的重复项) https://leetcode-cn.com/problems/remove-duplicates-from-sorted-array/description/ 题目描述 给定一个排序数组,你需要在 原地 删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新...