What if duplicates are allowed at mosttwice? For example, Given sorted array A =[1,1,1,2,2,3], Your function should return length =5, and A is now[1,1,2,2,3]. 说明: 1)设个标志可实现 实现: 1classSolution {2public:3intremoveDuplicates(intA[],intn) {4if(0==n)return0;5int...
Given a sorted array, remove the duplicates in place such that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input arraynums=[1,1,2], Your function should return len...
Given a sorted arraynums, remove the duplicatesin-placesuch that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. Example 1: Given nums = [1,1,2], Your fun...
- LeetCodeleetcode.com/problems/remove-duplicates-from-sorted-array/description/ 解题思路 双指针 class Solution { public: int removeDuplicates(vector<int>& nums) { if(nums.size() == 0) return 0; int i = 0, j = 1; while(j < nums.size()) { if(nums[i] != nums[j]) { i+...
英文网址:26. Remove Duplicates from Sorted Array。 中文网址:26. 删除排序数组中的重复项。 思路分析 求解关键:简单来说,得记录一下当前遍历的元素之前的那个元素,用作比较。 参考解答 参考解答1 import java.util.Arrays; // 常规题目:这里利用到数组的有序性,如果遇到和上一个一样的元素,就什么都不做 ...
LeetCode: 82. Remove Duplicates from Sorted List II 题目描述 Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5...
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
unique巧解 Jeremy_LeeL1发布于 2020-03-243.2kC++ 解题思路 这题其实可以直接用c++自带的unique函数,只要一行代码 代码 class Solution { public: int removeDuplicates(vector<int>& nums) { return unique(nums.begin(),nums.end())-nums.begin(); } }; ...
26. 删除有序数组中的重复项 - 给你一个 非严格递增排列 的数组 nums ,请你 原地 [http://baike.baidu.com/item/%E5%8E%9F%E5%9C%B0%E7%AE%97%E6%B3%95] 删除重复出现的元素,使每个元素 只出现一次 ,返回删除后数组的新长度。元素的 相对顺序 应该保持 一致 。然后返回 n
Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. 增加一个count来计数,从左至右遍历,遇到相同的直接del,否则count += 1 classSolution:defremoveDuplicates(self,nums):""" ...