Can you solve this real interview question? Remove Duplicates from Sorted List II - Given the head of a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. Return the linked list sorted
LeetCode-Remove Duplicates from Sorted List II 考略最笨的方法:遇到值相同的就删除一个。 对于只出现一次的数,采用尾插法插入新的队列。 假设p指向当前节点,q指向p的下一个节点,(下面我们用p表示p->val,即p代表p节点存储的数值)。 (1)p==q:删除p; (2)p!=q:把p放入新队列; 这里我们要注意第二种...
https://leetcode.com/problems/remove-duplicates-from-sorted-list-ii/ 不断定位出重复的段,然后删除这段。C++须要手动删除链表节点。 classSolution{public:ListNode*deleteDuplicates(ListNode* head){if(!head || !head->next)returnhead;ListNodedummy(0); dummy.next = head; ListNode *cur = &dummy, *st...
题目链接:https://leetcode.com/problems/remove-duplicates-from-sorted-list-ii/ 题目: distinct For example, Given1->2->3->3->4->4->5, return1->2->5. Given1->1->1->2->3, return2->3. 思路: 思路很简单,唯一要注意的是 删除操作加入头结点可以减少很多判断。 算法: public ListNode de...
LeetCode 题解之 82. Remove Duplicates from Sorted List II,82.RemoveDuplicatesfromSortedListII题目描述和难度题目描述:给定一个排序链表,删除所有含有重复数字的节点,只保留原始链表中没有重复出现的数字。示例1:输入:1->2->3->3->4->4->5输出:1
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this by modifyi…
Type:mediun Given a sorted arraynums, remove the duplicatesin-placesuch that duplicates appeared at mosttwiceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. ...
Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. 增加一个count来计数,从左至右遍历,遇到相同的直接del,否则count += 1 classSolution:defremoveDuplicates(self,nums):""" ...
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