1047. Remove All Adjacent Duplicates In String # 题目 # Given a string S of lowercase letters, a duplicate removal consists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can
LeetCode#1047-Remove All Adjacent Duplicates In String-删除字符串中的所有相邻重复项 一、题目 给出由小写字母组成的字符串 S,重复项删除操作会选择两个相邻且相同的字母,并删除它们。 在S 上反复执行重复项删除操作,直到无法继续删除。 在完成所有重复项删除操作后返回最终的字符串。答案保证唯一。 示例: 输入...
链接:https://leetcode-cn.com/problems/remove-all-adjacent-duplicates-in-string python # 1047.删除所有相邻的重复字符 class Solution: def removeDuplicates(self,s: str) -> str: """ 借助辅助栈,同则出栈,否则入栈,最后拼接字符返回,时间O(n), 空间最坏O(n) """ stack = [] foriinrange(len(...
https://leetcode-cn.com/problems/remove-all-adjacent-duplicates-in-string/ 耗时 解题:38 min 题解:10 min 题意 给出由小写字母组成的字符串 S,重复项删除操作会选择两个相邻且相同的字母,并删除它们。 在S 上反复执行重复项删除操作,直到无法继续删除。 在完成所有重复项删除操作后返回最终的字符串。答案...
string removeDuplicates(string s, int k) { int i, streak; // streak will store count of consecutive duplicates while(1){ i = streak = 1; bool removed = false; streak = (s[i] == s[i - 1] ? streak + 1 : 1); if(streak == k) s.erase(i - k + 1, k), streak = 1, ...
Can you solve this real interview question? Remove All Adjacent Duplicates In String - You are given a string s consisting of lowercase English letters. A duplicate removal consists of choosing two adjacent and equal letters and removing them. We repeat
题目 Given a string S of lowercase letters, a duplicate removal consists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we n...leetcode1047——Remove All Adjacent Duplicates In String 题目大意:一次遍历,删除字符串中所有的相邻重复...
1047.Remove All Adjacent Duplicates In String Given a stringSof lowercase letters, aduplicate removalconsists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can.
原题链接在这里:https://leetcode.com/problems/remove-all-adjacent-duplicates-in-string/ 题目: Given a stringSof lowercase letters, aduplicate removalconsists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can. ...
209. Remove All Adjacent Duplicates in String II刷题笔记,用栈来实现classSolution:defremovestack=collections.deque()dupliflen(stack)>0andletter==stack[-1]:duplicat