leetcode1047——Remove All Adjacent Duplicates In String 题目大意:一次遍历,删除字符串中所有的相邻重复字符,比如abbaca->ca 分析:用字符串实现栈。遍历字符串,如果当前字符和栈顶相同就弹栈,否则入栈。 代码: ...猜你喜欢Remove All Adjacent Duplicates in String II(C++删除字符串中的所有相邻重复项 II)...
LeetCode#1047-Remove All Adjacent Duplicates In String-删除字符串中的所有相邻重复项 一、题目 给出由小写字母组成的字符串 S,重复项删除操作会选择两个相邻且相同的字母,并删除它们。 在S 上反复执行重复项删除操作,直到无法继续删除。 在完成所有重复项删除操作后返回最终的字符串。答案保证唯一。 示例: 输入...
1047. Remove All Adjacent Duplicates In String # 题目# Given a string S of lowercase letters, a duplicate removal consists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can. Return the final string after all such...
Return the final string after all such duplicate removals have been made. It is guaranteed the answer is unique. Example 1: Input:"abbaca" Output:"ca" Explanation: For example, in "abbaca" we could remove "bb" since the letters are adjacent and equal, and this is the only possible mov...
string removeDuplicates(string s, int k) { int i, streak; // streak will store count of consecutive duplicates while(1){ i = streak = 1; bool removed = false; streak = (s[i] == s[i - 1] ? streak + 1 : 1); if(streak == k) s.erase(i - k + 1, k), streak = 1, ...
1047.Remove All Adjacent Duplicates In String Given a stringSof lowercase letters, aduplicate removalconsists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can.
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Can you solve this real interview question? Remove All Adjacent Duplicates in String II - You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them, causing the left and th
209. Remove All Adjacent Duplicates in String II刷题笔记,用栈来实现classSolution:defremovestack=collections.deque()dupliflen(stack)>0andletter==stack[-1]:duplicat
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