https://leetcode.com/problems/remove-duplicates-from-sorted-array/ 题意分析: 给定一个排好序的数组,去除重复的数,返回新数组的长度,不能申请额外的空间,超过新数组长度部分是什么数都无所谓。 题目思路: 这是一个很简单的题目,由于给定的数组已经排序,那么用i,j两个下标,i记录新数组的下标,j是原来数组下...
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory....
算法题目 Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array A = [1,1,2], Your function sh...
26. Remove Duplicates from Sorted Array Given a sorted arraynums, remove the duplicates in-place such that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-place ...
What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doesn't matter what you leave beyond the new length. ...
Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. ...
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. Example 1: Given nums = [1,1...
Therefore, we may eliminate duplicates from the array in this method. Algorithm: Array to be sorted first. Since we know that the first element will always be unique, we keep a reference called k that counts down the unique elements starting at 1. From i=0 to i=n-2, execute a loop....
To remove duplicates from a Python list while preserving order, create a dictionary from the list and then extract its keys as a new list: list(dict.fromkeys(my_list)).
本题和上一篇文章Remove Duplicates from Sorted Array类似,用一个变量存储其他元素的个数count,每遇见一个不等于val的元素,将其赋值给数组第count个位置处,并且count加1,最后返回count即可。 【代码】 python版本 代码语言:javascript 代码运行次数:0 运行 ...