Remove Duplicates from Sorted Array:从排列后的数组中删除重复元素 考察数组的基本操作: classSolution {publicintremoveDuplicates(int[] nums) {if(nums==null|| nums.length==0)return0;intindex = 1;for(inti =1; i<nums.length; i++){if(nums[i]!=nums[i-1]){ nums[index]=nums[i]; index++...
26. Remove Duplicates from Sorted Array 题目链接 思路一:单指针法,遍历数组,遇到和下一个元素不同的把这个元素按顺序保存到数组的前面,用指针记录保存的个数,注意数组只有一个元素和遍历到最后俩元素的特殊情况。 class Solution: def removeDuplicates(self,nums): sum = 0 if len(nums) <= 1: return 1 ...
class Solution { public int removeDuplicates(int[] nums) { int fixedIndex = 0; int currentValue = nums[0]-1; for(int i=0;i<nums.length;i++){ if (nums[i]>currentValue){ nums[fixedIndex] = nums[i]; currentValue = nums[i]; fixedIndex+=1; } } return fixedIndex; } } 题目信...
Remove Duplicates from Sorted Array II Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3],5, with the first five elements of nums being 1, 1...
LeetCode_26_Remove Duplicates from Sorted Array 题目描述:给定一个整型数组,要求去除重复的数据,返回去重后的数组长度 method1:双指针(官方题解) 题目给定一个已经排好序的序列,我们可以设置双指针,一个slow指针,一个fast指针。fast指针用于跳过重复的数据,slow指针用于记录非重复的数据,即fast指针当前所指数据如果...
- LeetCodeleetcode.com/problems/remove-duplicates-from-sorted-array/description/ 解题思路 双指针 class Solution { public: int removeDuplicates(vector<int>& nums) { if(nums.size() == 0) return 0; int i = 0, j = 1; while(j < nums.size()) { if(nums[i] != nums[j]) { i+...
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
class Solution { public int removeDuplicates(int[] nums) { int len = nums.length; if (nums == null || len == 0 ){ return 0 ; } int i = 0 ; int j = 1 ; while (j < len){ if (nums[i] != nums[j]){ nums[i+1] = nums[j]; ...
class Solution {public: int removeElement(vector& nums, int val) { int repeat = 0; for(int i = 0; i < nums.size(); i++) { if(nums[i] == val) repeat++; else nums[i - repeat] = nums[i]; } return nums.size() - repeat; ...
Remove Duplicates from Sorted Array 删除有序数组中重复的元素;返回新的长度;不允许新建额外的数组 解决思路 设立2个游标:游标index用来遍历数组,游标newLen用来插入元素 遍历数组,两两比较;如果不同,将index指向的元素复制到newLen指向位置;newLen与index各自右移 输出:...Remove...