二、Remove Duplicates from Sorted Array2.1 问题题目大意理解,就是对数组进行元素去重,然后返回去处重复之后的长度,无论我们对数组做了什么的修改,都没有关系的,只要保证再返回的长度之内的数组正确性即可。因为最后是根据长度来遍历的,因此我们不用担心。
https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/ Given a sorted array, remove the duplicates in place such that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For exam...
- LeetCodeleetcode.com/problems/remove-duplicates-from-sorted-array/description/ 解题思路 双指针 class Solution { public: int removeDuplicates(vector<int>& nums) { if(nums.size() == 0) return 0; int i = 0, j = 1; while(j < nums.size()) { if(nums[i] != nums[j]) { i+...
http://oj.leetcode.com/problems/remove-duplicates-from-sorted-array-ii/ 这道题跟Remove Duplicates from Sorted Array比較类似,差别仅仅是这里元素能够反复出现至多两次,而不是一次。事实上也比較简单。仅仅须要维护一个counter。当counter是2时,就直接跳过就可以,否则说明元素出现次数没有超,继续放入结果数组,若...
#26 Remove Duplicates from Sorted Array mob60475707d572 文章标签数组遍历数组其他文章分类代码人生 题目链接:https://leetcode.com/problems/remove-duplicates-from-sorted-array/ Given a sorted array, remove the duplicates in place such that each element appear onlyonceand return the new length....
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
题目如下: Given a sorted array, remove the duplicatesin-placesuch that each element appear onlyonceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. ...
该题设部分有两个主要的关键点,其一是数组自身有顺序;其二是数组的本身返回仍是以袁数组nums的内容返回,预期不是采用新数组方式。 具体的一些复杂要求,可以去查看相关题设说明。 方法一: 使用双指针的方法,两个指针比较来进行移动. 其中i代表慢的指针,需要更新nums数组的值 ...
26. Remove Duplicates from Sorted Array 数组中重复元素的移除:要求空间复杂度是常量级的 我的第一个想法还是跟 27. Remove Element里面的第一个相同,遇到重复的就移动数组,把前面的重复值覆盖了,但是这样的时间复杂度比较大O(n2) 提交结果果然不尽人意 这时候脑子里的第一个反应就是肯定还有更快的,然后想法...
Array after removing duplicate elements: 1, 2, 3, 4, 5 Time Complexity: O(n), traversing through elements of the array.Space Complexity: O(n), using HashSet to store elements. Remove Duplicates from Array Using Sorting In this approach, we first sort the array. When sorted, duplicate el...