二、Remove Duplicates from Sorted Array2.1 问题题目大意理解,就是对数组进行元素去重,然后返回去处重复之后的长度,无论我们对数组做了什么的修改,都没有关系的,只要保证再返回的长度之内的数组正确性即可。因为最后是根据长度来遍历的,因此我们不用担心。
Remove Duplicates from Sorted Array II (Java) For example, given sorted array A = [1,1,1,2,2,3], your function should return length = 5, and A is now [1,1,2,2,3]. 最多允许两个重复,输出结果数组。 解法1:当counter是2时,就直接跳过即可,否则说明元素出现次数没有超,继续放入结果数组...
Can you solve this real interview question? Remove Duplicates from Sorted Array - Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place [https://en.wikipedia.org/wiki/In-place_algorithm] such that each unique element
- LeetCodeleetcode.com/problems/remove-duplicates-from-sorted-array/description/ 解题思路 双指针 class Solution { public: int removeDuplicates(vector<int>& nums) { if(nums.size() == 0) return 0; int i = 0, j = 1; while(j < nums.size()) { if(nums[i] != nums[j]) { i+...
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this by modifyi…
题目链接:https://leetcode.com/problems/remove-duplicates-from-sorted-array/ 题目: once Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array nums =[1,1,2],2, with the first two elements of nums being1and2 ...
http://oj.leetcode.com/problems/remove-duplicates-from-sorted-array-ii/ 这道题跟Remove Duplicates from Sorted Array比較类似,差别仅仅是这里元素能够反复出现至多两次,而不是一次。事实上也比較简单。仅仅须要维护一个counter。当counter是2时,就直接跳过就可以,否则说明元素出现次数没有超,继续放入结果数组,若...
Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. 增加一个count来计数,从左至右遍历,遇到相同的直接del,否则count += 1 classSolution:defremoveDuplicates(self,nums):""" ...
题目: 在不额外创建数组的情况下,通过O(1),去掉已经排好序的数组重复元素,返回长度 Given a sorted array nums, remove the dupli...
26. 删除有序数组中的重复项 - 给你一个 非严格递增排列 的数组 nums ,请你 原地 [http://baike.baidu.com/item/%E5%8E%9F%E5%9C%B0%E7%AE%97%E6%B3%95] 删除重复出现的元素,使每个元素 只出现一次 ,返回删除后数组的新长度。元素的 相对顺序 应该保持 一致 。然后返回 n