在LeetCode第80题中,如何处理重复元素? 【原题】 Follow up for “Remove Duplicates”: What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, ...
Given input arraynums=[1,1,2], Your function should return length =2, with the first two elements ofnumsbeing1and2respectively. It doesn't matter what you leave beyond the new length. 思路: (1)虽然能AC,但是不对的思路:如果找到重复的数,就将其设置成一个很大的数,最后再排序一下,返回新的...
Leetcode: Remove Elements Given an array and a value, remove all instances of that value in place andreturnthenewlength. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 一次性通过的,比较顺利,从读题到编写到检查到通过,14分50秒,我在不断进步中...
Can you solve this real interview question? Remove Linked List Elements - Given the head of a linked list and an integer val, remove all the nodes of the linked list that has Node.val == val, and return the new head. Example 1: [https://assets.leetc
Remove all elements from a linked list of integers that have valueval. Example: Input: 1->2->6->3->4->5->6, val = 6 Output: 1->2->3->4->5 1. 2. 题解: 增加个头结点指向需要删除结点的前面就好了 classSolution{ public: ...
classSolution{ public: ListNode*removeElements(ListNode*head,intval) { if(head==NULL)returnhead; ListNode*p=head; ListNode*q=p->next; while(q!=NULL){ // cout<<q->val<<endl; if(q->val==val){ p->next=q->next; q=q->next; ...
https://leetcode.com/problems/remove-linked-list-elements 和常规的删除一个node的情况不同的是,它要求删除所有val为指定值的node。 这道题要注意一个点: head node 的值是指定值,和中间node的值为指定值,在操作上不一样。比较好的办法是,在head前创建一个dummy node,那么这两种情况的操作就一样,最后返回...
[LeetCode]--203. Remove Linked List Elements 简介:Remove all elements from a linked list of integers that have value val.Example Given: 1 –> 2 –> 6 –> 3 –> 4 –> 5 –> 6, val = 6 Return: 1 –> 2 –> 3 –> 4 –>...
203.Remove_Linked_List_Elements README.md 205.Isomorphic_Strings 206.Reverse_Linked_List 209.长度最小的子数组 21.Merge_Two_Sorted_Lists 215.数组中的第K个最大元素 217.Contains_Duplicate 219.Contains_Duplicate_II 22.括号生成 220.Contains_Duplicate_III 234.Palindrome_Linked_List...
class Solution { public: ListNode* removeElements(ListNode* head, int val) { ListNode* tem =head; while (true) { if (head == NULL) return NULL; if (tem->val != val) break; tem = tem->next; head = tem; } while(tem->next){ if(tem->next->val==val){ tem->next=tem->next...