方法1:优化版(减少存储 & 直接累加) defclassify(number):"""Classify a number as 'perfect', 'abundant', or 'deficient'."""ifnumber <=0:raiseValueError("Classification is only possible for positive integers.") divisor_sum =
下面是整个问题的完整代码: defis_perfect_number(num):ifsum_of_factors(num)==num:returnTrueelse:returnFalsedefsum_of_factors(num):sum=0foriinrange(1,num):ifnum%i==0:sum+=ireturnsumfornuminrange(1,1001):ifis_perfect_number(num):print(num) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. ...
static void Main(string[] args) { for (int i = 1; i < 1000; i++) { Program p = new Program(); 完全数 原创 UtopiaDJ 2013-10-17 19:03:40 395阅读 完全数 完全数的Python实现 完全数 原创 寂寞暴走伤 2016-06-12 20:26:13 1776阅读 ...
AI代码解释 classSolution:defcheckPerfectNumber(self,num:int)->bool:sum=1tmp=numifnum==0or num==1:returnFalsewhilenum%2==0:num/=2sum+=num+tmp/numreturnsum==tmp 已知完美数都以6或8结尾,所以才有了上面的方法,注意这不是寻找一个数所有因子的方法。使用6或8结尾这个小trick,实现更高效( > 95....
Did we define an interface for our duck? No! Did we program to the interface instead of the implementation? Yes! And, I find this so nice. As Alex Martelli points out in his well known presentation about Python software design patterns, “Teaching the ducks to type takes a while, but ...
Etudes for Programmers I got the idea for the"etudes"part of the name from this1978 bookbyCharles Wetherellthat was very influential to me when I was first learning to program. I still have my copy.
Decimal number : 1.44 Expected Output : Square root of 1.44 is : 1.2 exponential of 1.44 is : 4.220695816996552825673328929 Click me to see the sample solution 39. Decimal Global Context Retriever Write a Python program to retrieve the current global context (public properties) for all decimal. ...
A common use case for this capability is the factory pattern. The factory pattern defines an interface for creating objects on the fly in response to conditions that you can’t predict when you’re writing a program. You can implement a factory of user-defined objects using a function that ...
For example, it’s suitable in science, engineering, and computer graphics, where execution speed is more important than precision. Hardly any program requires higher precision than you can get with a floating-point anyway. Note: If you only need to use integers, then int will be an even ...
# Define a function named 'perfect_number' that checks if a number 'n' is a perfect number def perfect_number(n): # Initialize a variable 'sum' to store the sum of factors of 'n' sum = 0 # Iterate through numbers from 1 to 'n-1' using 'x' as the iterator for x in range(...