publicclassSolution{/***@param num:aninteger*@return: returns true when it isaperfect number and false when it is not*/public boolean checkPerfectNumber(intnum) {// write your code hereif(num==1)returnfalse;intsum =1;for(inti =2; i * i <=num; i++) {if(num% i ==0) {if(i...
We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example: Input: 28 Output: True Explanation: 28 =...
Python program to print perfect numbers from the given list of integers # Define a function for checking perfect number# and print that numberdefcheckPerfectNum(n):# initialisationi=2sum=1# iterating till n//2 valuewhilei<=n //2:# if proper divisor then add it.ifn % i==0:sum+=i...
Leetcode 507 Perfect Number 思路brute force的时间复杂度为O(n), 很简单但是可能会TLE,就不探讨了。 优化思路:(1)一种是循环到num/2的位置,会将所有的divisor都找一遍,时间复杂度仍然为O(n), 但是会减少一半(BigTheta(n/2));(2)循环到sqrt(num),这样会将所有因子对(pair(x,y))的x部分都找到,...
Python Code:# Define a function named 'perfect_number' that checks if a number 'n' is a perfect number def perfect_number(n): # Initialize a variable 'sum' to store the sum of factors of 'n' sum = 0 # Iterate through numbers from 1 to 'n-1' using 'x' as the iterator for x...
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代码(Python3) class Solution: dp: List[int] = [] def numSquares(self, n: int) -> int: # 使用类变量缓存计算结果,避免 TLE if not Solution.dp: Solution.dp = Solution.all_num_squares(10000) return Solution.dp[n] @staticmethod def all_num_squares(n: int) -> List[int]: # dp[i]...
LeetCode : Perfect Number We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect......
//C# program to check the given number is a//perfect number or not.usingSystem;classCheckPerfect{staticboolIsPerfect(intnumber){intsum=0;intiLoop=0;for(iLoop=1;iLoop<number;iLoop++){if(number%iLoop==0)sum=sum+iLoop;}if(sum==number){returntrue;}returnfalse;}staticvoidMain(string[]args)...
userPrompt = {'Enter floating point number 1 : ','Enter floating point number 2: '}; caUserInput = inputdlg(userPrompt, titleBar, 1, defaultValue); ifisempty(caUserInput),return,end;% Bail out if they clicked Cancel. % Convert to floating point from string...