示例 假设我们有一个数值列表[0.123, 1.234, 12.345, 123.456, 1234.567],我们希望将每个数值保留两位有效数字并自动补0。 numbers=[0.123,1.234,12.345,123.456,1234.567]fornumberinnumbers:rounded_number=round_to_two_decimal_places(number)print(rounded_number) 1. 2. 3. 4. 5. 运行以上代码,输出结果如下...
deffloat_to_two_decimal_places(number):number_str=str(number)result_str="{:.2f}".format(number)result=float(result_str)returnresult 1. 2. 3. 4. 5. 四、示例使用 我们可以通过以下代码来测试我们的函数: result=float_to_two_decimal_places(3.1415926)print(result) 1. 2. 这里我们调用了float_...
Python String: Exercise-31 with SolutionWrite a Python program to print the following numbers up to 2 decimal places with a sign.Sample Solution:Python Code:# Define a variable 'x' and assign it the value 3.1415926 (a positive floating-point number). x = 3.1415926 # Define a variable 'y'...
rounded_num = round(num) print("Rounded number:", rounded_num) 在这个示例中,将浮点数 10.8 四舍五入为最接近的整数。 四舍五入为指定精度的小数 num = 10.876 rounded_num = round(num, 2) print("Rounded number with 2 decimal places:", rounded_num) 在这个示例中,将浮点数 10.876 四舍五入...
>>> num = 4.123956>>> f"num rounded to 2 decimal places = {num:.2f}"'num rounded to 2 decimal places = 4.12'如果不做任何指定，那么浮点数用最大精度 >>> print(f'{num}')4.123956 格式化百分比数 >>> total = 87>>> true_pos = 34>>> perc = true_pos / total>>> perc0....
int((number - int(number)) * 100) print("Decimal part:", decimal) if decimal % 10...
1.1 数值型(number) 例子: a, b, c, d = 20, 5.5, True, 4+3j print(a, b, c, d) # 20 5.5 True (4+3j) print(type(a), type(b), type(c), type(d)) # <class 'int'> <class 'float'> <class 'bool'> <class 'complex'> Python也可以这样赋值: ...
def enforce_two_decimal_places(number): decimal_number = Decimal(str(number)) enforced_number = decimal_number.quantize(Decimal('0.00'), rounding=ROUND_HALF_UP) return enforced_number # 示例使用 number = 10 enforced_number = enforce_two_decimal_places(number) print(enforced_number) # 输出:...
pi = 3.141592653589793 formatted_string = "Pi is approximately {:.2f} or {:.5f} decimal places.".format(pi, pi) print(formatted_string) # 输出：Pi is approximately 3.14 or 3.14159 decimal places.注意事项 在使用format函数时，有一些技巧和注意事项可以帮助你更有效地使用它。了解不同的...
print count,y count+=1 if (y*y>num):up=y y=low+(y-low)/2 else:low=y y=up-(up-y)/2 return y print(sqrt_binary(5))print(sqrt(5))2：牛顿迭代 仔细思考一下就能发现，我们需要解决的问题可以简单化理解。从函数意义上理解：我们是要求函数f(x) = x²，使f(x) = ...