int dy[8] = {-2, -2, -1, -1, 1, 1, 2, 2}; int marked[MAX][MAX]; //标记 int pathx[MAX]; int pathy[MAX]; int flag, step; int p,q; int main(void) { int n; int i = 0; int j, k; scanf("%d", &n); while (i++ < n) { scanf("%d%d", &p, &q); for ...
POJ-2488-A Knight's Journey 解题报告: 1、DFS遍历,并且记录走过的路径(先数字代替),不重复地全部走完。 2、需要按照字典序输出,注意方向数组的方向顺序,并且从A1开始搜索。 3、DFS的参数用于记录状态转移量(x,y)和递归的深度(step)。 4、使用全局变量简化程序的设计。 AC代码: #include <iostream> #includ...
http://poj.org/problem?id=2488 给一个n1*n2的棋盘,从(0,0)出发,每次走日字形,能否不重复的遍历所有的点 用DFS即可,需要注意搜索的方向要按字典序 #include<stdio.h> #include<string.h> #include<stdlib.h> int n1,n2; int xx[30],yy[30]; int visit[30][30]; int flag; int dir[8][2]=...
题目链接:http://poj.org/problem?id=2488 A Knight's Journey Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 36695 Accepted: 12462 Description BackgroundThe knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around ...
http://poj.org/problem?id=2488 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one ...
POJ 2488(简单的深搜) 1. re: Pku 2774--Long Long Message(后缀树) 求教大牛,那个Lt属性是记录什么的 --dereky 2. re: POJ 2481(树状数组) @gzwzm06 哦,实在是不好意思,确实是那个地方,现在过了,谢谢了啊。 --Klion 3. re: POJ 2481(树状数组)...
POJ-2488,A Knight's Journey(DFS) Description: Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction and one square perpendicular to ...
POJ 2488 A Knight's Journey 题解 A Knight's Journey Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 26210 Accepted: 8950 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey ...
这样能通过编译么？你用的是#include<iostream>是c++的头文件，然后后面又来scanf();printf();这是c的写法！不一样的！这样是不行的！
《POJ2488 A Knights Journey 骑士巡游 DFS》(https://www.unjs.com)。注意搜索的顺序,因为要求字典序输出! 代码 #include<cstdio>#include<cstring>#include using namespace std;const int maxn = 30;int vis[maxn][maxn];int kase = 0;int width,high;int cnt;struct node { int x; char y;};...