leetcode 【 Plus One 】python 实现 题目: Given a non-negative number represented as an array of digits, plus one to the number. The digits are stored such that the most significant digit is at the head of the list. 代码:oj测试通过 Runtime: 47 ms 1classSolution:2#@param digits, a l...
https://leetcode.com/problems/plus-one/ 题意分析: 给定一个数组,将数加一,返回新的数组。比如[9,9],返回[1,0,0]。 题目思路: 这道题目很简单,尾数加1,然后如果进位就向前一个数字加1. 代码(Python): View Code
代码(Python3) class Solution: def plusOne(self, digits: List[int]) -> List[int]: # carry 表示当前位的进位,初始化为 1 ,表示对个位加 1 carry: int = 1 for i in range(len(digits) - 1, -1, -1): # 计算第 i 位的中间计算结果 digits[i] += carry # 计算对第 i - 1 位产生的...
题目地址:https://leetcode.com/problems/plus-one/ Total Accepted: 99274 Total Submissions: 294302 Difficulty: Easy 题目描述 Given a non-empty array of digits representing a non-negative integer, plus one to the integer. The digits are stored such that the most significant...
[Leetcode][python]Plus One/加一 题目大意 给一个由包含一串数字的列表组成的非负整数加上一。 注意点: 列表前面的数字表示高位 注意最高位也可能进位 解题思路 简单数学题 代码 方法一 class Solution(object): def plusOne(self, digits): """
Plus One.go中,如何处理进位问题? Leetcode Golang 66. Plus One.go 的时间复杂度是多少? 思路 注意处理有进位的情况 code 代码语言:javascript 代码运行次数:0 运行 AI代码解释 func plusOne(digits []int) []int { l := len(digits) for i := l - 1; i >= 0; i-- { if digits[i] < 9...
leetcode-66-Plus One 编程算法 Given a non-empty array of digits representing a non-negative integer, plus one to the integer. chenjx85 2019/03/14 3980 leetcode: explore-array-27 加一 python编程算法 https://leetcode-cn.com/explore/interview/card/top-interview-questions-easy/1/array/27/ ...
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One of them is marked in bold. Example 2: Input: N = 2, mines = [] Output: 1 Explanation: There is no plus sign of order 2, but there is of order 1. Example 3: Input: N = 1, mines = [[0, 0]] Output: 0 Explanation: There is no plus sign, so return 0. Note: ...
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