Python program to print perfect numbers from the given list of integers # Define a function for checking perfect number# and print that numberdefcheckPerfectNum(n):# initialisationi=2sum=1# iterating till n//2 valuewhilei<=n //2:# if proper divisor then add it.ifn % i==0:sum+=...
This Blog provides a comprehensive guide to creating prime numbers, perfect numbers, and reverse numbers in Python. Learn More about Python Numbers!
首先,我们需要定义一个名为perfect_number的函数,它接受一个参数limit,该参数有一个默认值1000。这个函数将用于寻找并返回在1到limit范围内的所有完美数。 python def perfect_number(limit=1000): # 函数体将在下面编写 遍历从1到limit的所有整数: 在函数内部,我们将使用一个for循环来遍历从1到limit(包括limit...
AI检测代码解析 defis_perfect_number(num):ifsum_of_factors(num)==num:returnTrueelse:returnFalsedefsum_of_factors(num):sum=0foriinrange(1,num):ifnum%i==0:sum+=ireturnsumfornuminrange(1,1001):ifis_perfect_number(num):print(num) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. ...
Problem4: PerfectNumber.java Problem5: ArmstrongNumbers.java Pyramid.java: (Printing numbers in a pyramid pattern) Write down a program in Java with anested for loop that prints the following output (powers of 2) for any number of lines:Here is a sample run:Enter the number of lines: 8...
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//C# program to check the given number is a//perfect number or not.usingSystem;classCheckPerfect{staticboolIsPerfect(intnumber){intsum=0;intiLoop=0;for(iLoop=1;iLoop<number;iLoop++){if(number%iLoop==0)sum=sum+iLoop;}if(sum==number){returntrue;}returnfalse;}staticvoidMain(string[]args)...
In this tutorial we will see how can we check in Python if a given number is a perfect square or not without using the sqrt function in Python.
Q17.Perfect number Question: A number is called a “perfect number” if it is equal to the sum of its factors. For example, 6 has a factor of 1,2,3, and 6 = 1 + 2 + 3, so 6 is the perfect number. Find the perfect number in a certain range. Python Code: def wanshu(a)...
Python Code:# Define a function named 'perfect_number' that checks if a number 'n' is a perfect number def perfect_number(n): # Initialize a variable 'sum' to store the sum of factors of 'n' sum = 0 # Iterate through numbers from 1 to 'n-1' using 'x' as the iterator for x...