代码(Python3) # 每个方向的位置改变量 # 0: 向上走 1 步 # 1: 向右走 1 步 # 2: 向下走 1 步 # 3: 向左走 1 步 DIRS: List[Tuple[int, int]] = [(-1, 0), (0, 1), (1, 0), (0, -1)] class Solution: def minimumEffortPath(self, heights: List[List[int]]) -> int: ...
题目地址:https://leetcode-cn.com/problems/path-with-minimum-effort/ 题目描述 你准备参加一场远足活动。给你一个二维rows x columns的地图heights,其中heights[row][col]表示格子(row, col)的高度。一开始你在最左上角的格子(0, 0),且你希望去最右下角的格子(rows-1, columns-1)(注意下标从 0 开始...
利用二分查找依次选择x;利用dfs或bfs查找通路。 c++代码:(转自leetcode) class Solution { private: static constexpr int dirs[4][2] = {{-1, 0}, {1, 0}, {0, -1}, {0, 1}}; public: int minimumEffortPath(vector<vector<int>>& heights) { int m = heights.size(); int n = heights...
Minimum Path Sum LeetCode上的64题:https://leetcode.com/problems/minimum-path-sum/ 文章目录 Minimum Path Sum 题目 题解 代码 题目 对二维m*n数组,求一条从左上到右下的路径,使得路径经过的数字的累计和最小。注意“行走”时只能往下或往右 Example: 题解 题目作为DP题目很简...[...
col]represents the height of cell(row, col). You are situated in the top-left cell,(0, 0), and you hope to travel to the bottom-right cell,(rows-1, columns-1)(i.e.,0-indexed). You can moveup,down,left, orright, and you wish to find a route that requires the minimumeffort...
链接:https://leetcode-cn.com/problems/path-with-minimum-effort 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 这是一道图论/搜索的题,我直接给思路。这道题的解法涉及到Dijikstra算法,因为这道题求的是带权重的图的traverse问题。根据题意,图的每一条边的权重是由每两个相邻的cell....
Path With Minimum Effort (M) 题目 You are a hiker preparing for an upcoming hike. You are given heights, a 2D array of size rows x columns, where height