题目地址:https://leetcode-cn.com/problems/path-with-minimum-effort/ 题目描述 你准备参加一场远足活动。给你一个二维rows x columns的地图heights,其中heights[row][col]表示格子(row, col)的高度。一开始你在最左上角的格子(0, 0),且你希望去最右下角的格子(rows-1, columns-1)(注意下标从 0 开始...
# 每个方向的位置改变量 # 0: 向上走 1 步 # 1: 向右走 1 步 # 2: 向下走 1 步 # 3: 向左走 1 步 DIRS: List[Tuple[int, int]] = [(-1, 0), (0, 1), (1, 0), (0, -1)] class Solution: def minimumEffortPath(self, heights: List[List[int]]) -> int: m, n = len(...
当我们遍历到某个坐标的时候,如果已经记录的effort更小则无需更新;如果重新计算的newEffort更小则需要更新effort数组并用这个值代入下一轮的BFS计算。 时间O(m * n * nlogn) 空间O(mn) Java实现 1classSolution {2publicintminimumEffortPath(int[][] heights) {3intm =heights.length;4intn = heights[0]...
Minimum Path Sum LeetCode上的64题:https://leetcode.com/problems/minimum-path-sum/ 文章目录 Minimum Path Sum 题目 题解 代码 题目 对二维m*n数组,求一条从左上到右下的路径,使得路径经过的数字的累计和最小。注意“行走”时只能往下或往右 Example: 题解 题目作为DP题目很简...[...
A route'seffortis themaximum absolute differencein heights between two consecutive cells of the route. Returnthe minimumeffortrequired to travel from the top-left cell to the bottom-right cell. Example 1: Input: heights = [[1,2,2],[3,8,2],[5,3,5]] ...
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https://leetcode-cn.com/problems/path-with-minimum-effort/ keywords: dfs, bfs, 并查集 ##分析: 首先进行模型抽象,将地图抽象为图论模型。 地图中每个格子抽象为一个节点;每个上下或左右相邻的节点之间对应一条无向边,边权值
1631. Path With Minimum Effort (M) Path With Minimum Effort (M) 题目 You are a hiker preparing for an upcoming hike. You are givenheights, a 2D array of sizerows x columns, whereheights[row][col]represents the height of cell(row, col). You are situated in the top-left cell,(0,...