SOLUTION 2: 使用DFS + Memory也可以解决问题。当前到终点有2种方式,往右,往下,两种路线,取一个较小的路线就行了。 View Code GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/dp/MinPathSum_1222_2014.java
解法没变,就是边界的处理上不一样,这个是先初始化边界了。 Solution 3 () classSolution {public:intminPathSum(vector<vector<int>>&grid) {intdp[grid.size()][grid[0].size()]; dp[0][0] = grid[0][0];//init first rowfor(inti =1; i < grid[0].size(); i ++){ dp[0][i] = d...
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 思路分析: 我们只要保证当前的第k歩是最小的,然后第k+1歩同样选择...
题目地址:https://leetcode.com/problems/minimum-path-sum/description/ 题目描述 Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or rig...
class Solution { public: int minPathSum(vector<vector<int> > &grid) { int r = grid.size(); if (r < 1) return 0; int c = grid[0].size(); vector<int> table(c); if (c-1>=0) table[c-1] = grid[r-1][c-1];
【CSON】LeetCode讲解 64. Minimum Path Sum发布于 2022-01-13 11:41 · 274 次播放 赞同添加评论 分享收藏喜欢 举报 力扣(LeetCode)算法编程程序员面试移动社交 写下你的评论... 还没有评论,发表第一个评论吧相关推荐 14:31 不是这假期也没告诉我是这么过的呀,早知道是这么个...
classSolution{ private: intminSum; vector<vector<int>>my_grid; introwMax; intcolMax; public: voidtra(inti,intj,intsum){ sum+=my_grid[i][j]; if(j==colMax-&&i<rowMax) { ++i; for(i;i<rowMax;++i) { sum+=my_grid[i][j]; ...
https://leetcode.com/problems/minimum-path-sum/description/ 这个题目写了三遍,才写出正确的Solution。前两个错误,都是因为初始化错误。 classSolution{publicintminPathSum(int[][]grid){introwNum=grid.length;intcolNum=grid[0].length;int[][]dp=newint[rowNum][colNum];// initializationdp[0][0]=...
classMinimumPathSum{funminPathSum(grid:Array<IntArray>):Int{valdp=Array(grid.size){Array(grid[0].size){0}}for(iingrid.indices){for(jingrid[0].indices){if(i==0&&j==0){dp[0][0]=grid[0][0]}elseif(i==0){dp[0][j]=dp[0][j-1]+grid[i][j]}elseif(j==0){dp[i][0]...
int minPathSum(vector<vector<int> > &grid) { // Start typing your C/C++ solution below // DO NOT write int main() function int n=grid.size(); if(n<=0) return 0; int m=grid[0].size(); vector<vector<long> >M; M.resize(n); for(int i=0;i<n;i++){ M[i].resize(m,...