Pascal's Triangle leetcode java(杨辉三角) 题目: GivennumRows, generate the firstnumRowsof Pascal's triangle. For example, givennumRows= 5, Return [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] 题解: 既然讲到了Pascal‘s Triangle,即杨辉三角。那么就先去Wikipedia上面复习...
[LeetCode] 118. Pascal's Triangle Given an integer numRows, return the first numRows of Pascal's triangle. In Pascal's triangle, each number is the sum of the two numbers directly above it as shown: Example 1: Input: numRows = 5 Output: [[1],[1,1],[1,2,1],[1,3,3,1],[...
Given a non-negative integer numRows, generate the first numRows of Pascal's triangle. 1. In Pascal's triangle, each number is the sum of the two numbers directly above it. Example: Input: 5 Output: [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] 1. 2. 3. 4...
leetcode 118. Pascal's Triangle 杨辉三角形 Given numRows, generate the first numRows of Pascal’s triangle. For example, given numRows = 5, Return [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] 这个就是中国最伟大的杨辉三角形的问题。 代码如下: import java.util.Array...
## LeetCode 118classSolution:defgenerate(self,num_rows):## The number of rowstriangle=[]forrow_numinrange(num_rows):## For a specific rowrow=[Nonefor_inrange(row_num+1)]## All None for this rowrow[0]=1## The most left number = 1row[-1]=1## The most right number =1## ...
本题是 LeetCode 118 这题的加强版,需要将空间复杂度优化为 O(n) 。 空间复杂度为 O(n ^ 2) 的方法很简单,按照题意从第一层开始计算即可。 对于每一个位置 (i, j) 有 dp[i][j] = dp[i - 1][j - 1] + dp[i][j] 。 注意边界情况,当 j == 0 || j == i 时, dp[i][j] = ...
Leetcode - Pascal's Triangle Paste_Image.png My code: import java.util.ArrayList;import java.util.List;publicclassSolution{publicList<List<Integer>>generate(intnumRows){List<List<Integer>>result=newArrayList<List<Integer>>();if(numRows<=0)returnresult;List<Integer>newList=newArrayList<Integer>(...
版本3:参考https://leetcode.com/problems/pascals-triangle/discuss/38171/Maybe-shortest-c%2B%2B-solution 其思想就是直接使用二维数组。注意二维数组初始化,以及resize用法(http://www.cplusplus.com/reference/vector/vector/resize/) vector<vector<int>>generate(intnumRows){vector<vector<int>>results(numRows...
LeetCode 118:杨辉三角 II Pascal's Triangle II 编程算法 Given a non-negative index k where k ≤ 33, return the kth index row of the Pascal's triangle. 爱写bug 2019/07/07 3590 leetcode # 118:Pascal's Triangle 杨辉三角 java Given a non-negative integer numRows, generate the ...
Can you solve this real interview question? Pascal's Triangle II - Given an integer rowIndex, return the rowIndexth (0-indexed) row of the Pascal's triangle. In Pascal's triangle, each number is the sum of the two numbers directly above it as shown: [h