Can you solve this real interview question? Pascal's Triangle II - Given an integer rowIndex, return the rowIndexth (0-indexed) row of the Pascal's triangle. In Pascal's triangle, each number is the sum of the two numbers directly above it as shown: [h
publicstaticvoidmain(String[] args){ Easy_119_PascalTriangleII instance =newEasy_119_PascalTriangleII();introwIndex =3;longstart = System.nanoTime(); List<Integer> list = instance.getRow(rowIndex);longend = System.nanoTime(); System.out.println("getRow---输入:"+rowIndex+" , 输出:"+li...
vector<int> getRow(introwIndex) {int*arr =newint[rowIndex+2];int*arr1 =newint[rowIndex+2]; std::vector<int>v;if(rowIndex ==0) { v.push_back(1);returnv; } arr[1] =1; arr[2] =1;int*src, *des;for(inti =2; i <= rowIndex; ++i) {if((i &1)==0){ src=arr; des...
本题是 LeetCode 118 这题的加强版,需要将空间复杂度优化为 O(n) 。 空间复杂度为 O(n ^ 2) 的方法很简单,按照题意从第一层开始计算即可。 对于每一个位置 (i, j) 有 dp[i][j] = dp[i - 1][j - 1] + dp[i][j] 。 注意边界情况,当 j == 0 || j == i 时, dp[i][j] = ...
思路:最简单的方法就是依照【Leetcode】Pascal's Triangle 的方式自顶向下依次求解,但会造成空间的浪费。若仅仅用一个vector存储结果。在下标从小到大的遍历过程中会改变vector的值,如[1, 2, 1] 按小标从小到大累计会变成[1, 3, 4, 1]不是所求解,因此能够採取两种解决方法,简单的一种则是使用两个vector,...
leetcode 119. Pascal's Triangle II Given a non-negative indexkwherek≤ 33, return thekthindex row of the Pascal's triangle. Note that the row index starts from 0. In Pascal's triangle, each number is the sum of the two numbers directly above it....
题目参考见 Q118 Pascal's Triangle 要求空间复杂度为O(k),所以构造一半。最后根据奇、偶行构造完整的返回值。思路一样,即第k行的数是由第k-1行的数得到的,因此循环构造即可。 Python实现: class Solution: def getRow(self, rowIndex): """ :type rowIndex: int :rtype: List[int] """ if rowIndex...
提交结果: 执行用时:1ms,在Pascal'sTriangle的Java提交中击败了97.86%的用户 内存消耗:33.6MB,在Pascal'sTriangle的Java提交中击败了39.51%的用户
LeetCode——Pascal's Triangle II Given an index k, return the kth row of the Pascal's triangle. For example, given k = 3, Return [1,3,3,1]. Note: Could you optimize your algorithm to use only O(k) e...【leetcode】Pascal's Triangle II Question: Given an index k, return ...
leetcode 118[easy]---Pascal's Triangle 难度:easy Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5, Return 思路:帕斯卡三角形。每层的每个元素就是上一行两个相邻元素相加(第一个和最后一个元素是1)。用两个for循环实现。......