int palindrome=0; int revers=x; if(revers<0) return false; else{ while(revers>0){ int m=revers%10; palindrome=m+palindrome*10; revers=revers/10; } if(palindrome==x) return true; else return false; } } }
Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space. You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed ...
Input: -121 Output: false Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome. 说明:从左向右为-121,从右向左为121-,所以它不是回文数 Example 3: Input: 10 Output: false Explanation: Reads 01 from right to left. There...
针对这两点改进之后,思路二的算法用 Java 代码描述如下: public boolean isPalindrome(int x) { if(x < 0 || (x % 10 == 0 && x != 0)) return false; int revertedNumber = 0; while(x > revertedNumber) { revertedNumber = revertedNumber * 10 + x % 10; x /= 10; } return x == ...
[LeetCode][Java] Palindrome Number 题目: Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space....
除法之后保留整数结果 - Floor division - division that results into whole number adjusted to the left in the number linereturnx==y## 改进版## LeetCode 9, 回文数,不转换为字符串的写法1:## 这个解法的详细解读,可参考下一个解法classSolution:defisPalindrome(self,x:int)->bool:ifx<0:returnFalse...
判断一个整数是否是回文数。回文数是指正序(从左向右)和倒序(从右向左)读都是一样的整数。 【示例1】 输入: 121 输出: true 【示例1】 输入: -121 输出: false 解释: 从左向右读, 为 -121 。 从右向左读, 为 121- 。因此它不是一个回文数。
LeetCode NO. 9 Palindrome Number LeetCode 第9题 回文数 DIFFICULTY(难度) EASY 容易 DESCRIPTION(题面) Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. 判断一个整数是否是回文数,回文数就是正读反读都相同的数字 ...
LeetCode——009 Palindrome Number Description Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true 1 2 Example 2: Input: -121 Output: false...
**解析:**Version 1,统计字符个数,偶数的直接相加,奇数的减1相加,存在奇数则最终结果加1,即位于正中间。