Shortest Palindrome Given a string S, you are allowed to convert it to a palindrome by adding characters in front of it. Find and return the shortest palindrome you can find by performing this transformation. For example: Given "aacecaaa", return "aaacecaaa". Given "abcd", return "dcbabc...
public String longestPalindrome(String s) { if (s == null || s.length() < 2) return s; //return as result String longest = s.substring(0, 1); for (int i = 0; i < s.length()-1; i++) { //get 'ABA' type palindrome String cur = getPalindrome(s, i, i); //get 'ABBA...
String sPlus=s+"#"+reverse(s);int[] PI=KMPpreprocess(sPlus);intpalinIndex=Math.min(PI[PI.length-1],s.length()-1); String nonPalin=s.substring(palinIndex+1); String Palin=s.substring(0,palinIndex+1);returnreverse(nonPalin)+Palin+nonPalin; }...
publicclassSolution {publicString shortestPalindrome(String s) {for(inti=s.length();i>=1;i--)if(isPalindrome(s.substring(0, i)))returnnewStringBuilder(s.substring(i)).reverse()+s;return""; }staticbooleanisPalindrome(String s){intleft=0,right=s.length()-1;while(left<right)if(s.charAt...
StringBuilder in = new StringBuilder(); int a = x; while(a!=0) { in.append(a%10); a/=10; } String o = String.valueOf(x); if(o.equals(in.toString())) { return true; }else { return false; } } } 1. 2. 3. 4.
Return true if it is possible to form a palindrome string, otherwise return false. Notice that x + y denotes the concatenation of strings x and y. Example 1: Input: a = "x", b = "y" Output: true Explaination: If either a or b are palindromes the answer is true since you can sp...
Return true if it is possible to form a palindrome string, otherwise return false. Notice that x + y denotes the concatenation of strings x and y. Example 1: Input: a = "x", b = "y"Output: trueExplaination: If either a or b are palindromes the answer is true since you can split...
public static boolean isPalindrome(String s) { if(s==null || s.length()==0 || s.length()==1){ return true; } int i = 0, j = s.length()-1; while(i <= j){ // Java中用Character.isLetterOrDigit 来检查是否是alphanumeric ...
Leetcode 1048. Longest String Chain 编程算法 **解析:**Version 1,先根据字符串长度对数组排序,然后根据长度分到不同的组里,按长度遍历组,如果下一组的字符串长度比当前组多1个,则遍历两组的所有元素,满足条件前辈子串,则下一组子串的字符链长度在当前子串长度的基础上加1,其实就是一个广度优先搜索的过程。
size(); i++) { if(fun(num[x][i] - 1, y + 1)) return true; } return false; } bool checkPartitioning(string s) { Tree tree = Tree(); tree.init(); for (int i = 0; i < s.length(); i++) { tree.add(s[i]); vector<int> m; int x = tree.last; m.push_back(i...