Can you solve this real interview question? Convert Binary Number in a Linked List to Integer - Given head which is a reference node to a singly-linked list. The value of each node in the linked list is either 0 or 1. The linked list holds the binary rep
02 第一种解法 最直接解法,将正整数转为二进制字符串,借助包装类Integer的toBinaryString方法实现,然后对字符串的字符进行遍历,如果相邻的字符相等了,直接返回false。 publicbooleanhasAlternatingBits(intn){Stringstr=Integer.toBinaryString(n);for(inti=1; i<str.length(); i++) {if(str.charAt(i) == st...
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Github 同步地址: https://github.com/grandyang/leetcode/issues/1290 参考资料: https://leetcode.com/problems/convert-binary-number-in-a-linked-list-to-integer/ https://leetcode.com/problems/convert-binary-number-in-a-linked-list-to-integer/discuss/629087/Detailed-explanation-Java-%3A-faster-than...
题目地址:https://leetcode-cn.com/problems/number-of-steps-to-reduce-a-number-in-binary-representation-to-one/ 题目描述 给你一个以二进制形式表示的数字s。请你返回按下述规则将其减少到 1 所需要的步骤数: 如果当前数字为偶数,则将其除以 2 。
leetcode 405. Convert a Number to Hexadecimal Given an integer, write an algorithm to convert it to hexadecimal. For negative integer,two’s complementmethod is used. Note: All letters in hexadecimal (a-f) must be in lowercase. The hexadecimal string must not contain extra leading0s. If ...
【Binary Indexed Tree/树状数组】307. Range Sum Query - Mutable 3915 -- 9:29 App LeetCode 920. Number of Music Playlists 186 -- 10:33 App [English] LeetCode 233. Number of Digit One 399 -- 12:49 App LeetCode 1074. Number of Submatrices That Sum to Target 1329 8 10:24 App ...
本题代码和文字解析: https://github.com/wisdompeak/LeetCode/tree/master/Dynamic_Programming/1639.Number-of-Ways-to-Form-a-Target-String-Given-a-Dictionary残酷刷题群:https://wisdompeak.github.io/lc-score-board/视频专辑列表
res = last > 9 ? mp[last] + res : to_string(last) + res; num >>= 4; } return res; } }; Discuss const string HEX = "0123456789abcdef"; class Solution { public: string toHex(int num) { if (num == 0) return "0"; ...
给你一个二进制字符串s,现需要将其转化为一个交替字符串。请你计算并返回转化所需的最小字符交换次数,如果无法完成转化,返回-1。 交替字符串是指:相邻字符之间不存在相等情况的字符串。例如,字符串"010"和"1010"属于交替字符串,但"0100"不是。 任意两个字符都可以进行交换,不必相邻。