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Solution that I came up during contest: Binary search on answer. If we can delete a subarray of length k to make the array sorted, then a longer length is also sufficient because removing elements from a sorted array preserves the sorted order. So we can binary search in range [0, N -...
思路:对于一棵BST来说,它的中序遍历的值正好是从大到小排列的,因此可以根据中序遍历来判断二叉树是否是BST。 Answer: /*** Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * }*/publicclassSol...
来看看“别人家的代码”：一. 树1）求二叉树的高度（Maximum Depth of Binary Tree）// LeetCode, ...
com/problems/all-nodes-distance-k-in-binary-tree/8. Pattern: Tree Depth First Search，...
The answer is2. Because the sum of rectangle[[0, 1], [-2, 3]]is 2 and 2 is the max number no larger than k (k = 2). Note: The rectangle inside the matrix must have an area > 0. What if the number of rows is much larger than the number of columns?
第C实现LeetCode108.将有序数组转为二叉搜索树LeetCode 108.Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树 Given an array where e
Replace Elements with Greatest Element on Right Side 1300. Sum of Mutated Array Closest to Target 1302. Deepest Leaves Sum 1304. Find N Unique Integers Sum up to Zero 1305. All Elements in Two Binary Search Trees 1306. Jump Game III 1313. Decompress Run-Length Encoded List 1317. Convert ...
【解答】要划分数组成两个部分,这两个部分各自的和相等。 其实这道题可以问 k 个部分,两个部分是一个强化了的条件。整个数组的和(sum)是可以很容易得到的,那么分成两个部分,每个部分的和(sum/2)也就可以很容易得到了。于是这道题就变成了,能不能从数组中找出一些数,使之和为 sum/2?搜索求解即可。 求解...
median of two sorted array: binary search of k in the kth element kth smallest element in a sorted matrix: binary search of guessed number and find its position in matrix kth smallest number in multiplication table: basically kthe smallest element in a sorted matrix. Guess the answer and bin...