接着,我们要开始处理nums1的数据了,遍历其中的元素,如果能够在HashMap中找到对应的值,就取其value作为结果数组的元素值,否则取-1作为默认值。 publicint[]nextGreaterElement3(int[] nums1,int[] nums2) {int[] result =newint[nums1.length]; Map<Integer, Integer> map
Can you solve this real interview question? Next Greater Element I - The next greater element of some element x in an array is the first greater element that is to the right of x in the same array. You are given two distinct 0-indexed integer arrays num
Next Greater Element II Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which m...
Next Greater Element I ...[LeetCode] 496. Next Greater Element I 题目内容 https://leetcode-cn.com/problems/next-greater-element-i/ 给定两个没有重复元素的数组 nums1 和 nums2 ,其中nums1 是 nums2 的子集。找到 nums1 中每个元素在 nums2 中的下一个比其大的值。 ......
next-greater-element-I 【描述】:You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1’s elements in the corresponding places of nums2. ...
Next Greater Element I? Leetcode 496. Next Greater Element I的时间复杂度是多少? 1. Description 2. Solution **解析:**Version 1,由于元素是唯一的,通过循环找出每个nums2中的满足条件结果保存到字典中,遍历nums1,获得结果。Version 2通过使用栈来寻找满足条件的结果,减少搜索时间。 Version 1 代码语言:...
简介:LeetCode之Next Greater Element I 1、题目 You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.The Next Greater Number of a number x in...
https://leetcode.com/problems/next-greater-element-i/#/description 题目: You are given two arrays (without duplicates)nums1andnums2wherenums1’s elements are subset ofnums2. Find all the next greater numbers fornums1's elements in the corresponding places ofnums2. ...
For number 2 in the first array, the next greater number for it in the second array is 3. For number 4 in the first array, there is no next greater number for it in the second array, so output -1. 给你两个数组,为数组1和数组2,数组1为数组2的子集。找出数组1的每一个元素在数组2中...
1 读题:LeetCode 496E 下一个最大元素 2 解题思路 单调栈(栈底最大)的作用在于: 保持栈底始终是一个全栈最大的数值; 目标原来过来,和栈顶的元素对比(此时要求栈非空),如果栈顶的元素比它大,那么就找到了一个离它最近的、且比它大的元素;