publicintnextGreaterElement(int n){String value=String.valueOf(n);char[]digits=value.toCharArray();int i=digits.length-1;//找到小于右侧任意值的第一个正整数while(i>0){if(digits[i-1]<digits[i]){break;}i--;}if(i==0){return-1;}//找到该整数右侧大于该整数的最小整数int maxIndex=i,j...
next_permutation(str.begin(), str.end());longlongres =stoll(str);return(res > INT_MAX || res <= n) ? -1: res; } }; 类似题目: Next Greater Element II Next Greater Element I 参考资料: https://discuss.leetcode.com/topic/85740/c-4-lines-next_permutation https://discuss.leetcode....
intnextGreaterElement(intn) { string s = to_string(n); if(s.length() == 1) { return-1; } /* find the first decreasing digit from the right, eg: 59876, 5 is the first decreasing digit */ inti = s.length() - 2;// 21 -> i = 0; 59876 -> i = 3 for(; i >= 0 &&...
[LeetCode] Next Greater Element III 下一个较大的元素之三
Subscribe to unlock. Thanks for using LeetCode! To view this solution you must subscribe to premium. Subscribe C++ Auto 1 2 3 4 5 6 class Solution { public: int nextGreaterElement(int n) { } }; Saved Ln 1, Col 1 Case 1 Case 2...
Leetcode 556. Next Greater Element III 1. Description 2. Solution **解析:**Version 1,先将数字n变为字符数组,要找最小的大于n的数,则应该从右往左开始,依次寻找第i位字符右边的大于当前字符的最小数字,然后互换二者位置,由于新数字的第i位字符大于n中的第i位字符,因此新数字i位之后的字符应该从小到大...
publicintnextGreaterElement(intn){ String value =String.valueOf(n);char[]digits = value.toCharArray();inti = digits.length -1;//找到小于右侧任意值的第一个正整数while(i >0) {if(digits[i-1]< digits[i]) { break; } i--; }if(i==0) { ...
【Leetcode】556. Next Greater Element III 1 要注意结果,因为可能结果超出32bit能表示的范围了 2 思路是https://leetcode.com/problems/next-greater-element-iii/discuss/101824/Simple-Java-solution-(4ms)-with-explanation.
LeetCode题目:503. Next Greater Element II Given acircular array (the next element of the last element is the first element of the array),print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the...
503. Next Greater Element II # 题目 # Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to