next_permutation(str.begin(), str.end());longlongres =stoll(str);return(res > INT_MAX || res <= n) ? -1: res; } }; 类似题目: Next Greater Element II Next Greater Element I 参考资料: https://discuss.leetcode.com/topic/85740/c-4-lines-next_permutation https://discuss.leetcode....
intnextGreaterElement(intn) { string s = to_string(n); if(s.length() == 1) { return-1; } /* find the first decreasing digit from the right, eg: 59876, 5 is the first decreasing digit */ inti = s.length() - 2;// 21 -> i = 0; 59876 -> i = 3 for(; i >= 0 &&...
复制 classSolution:defnextGreaterElement(self,n:int)->int:digits=list(str(n))i=len(digits)-2whilei>-1and digits[i]>=digits[i+1]:i-=1ifi==-1:return-1j=i+1whilej<len(digits)and digits[j]>digits[i]:j+=1j-=1digits[i],digits[j]=digits[j],digits[i]result=int(''.join(digits...
leetcode556. Next Greater Element III 题目要求 Given a positive32-bitintegern, you need to find the smallest32-bitinteger which has exactly the same digits existing in the integernand is greater in value than n. If no such positive32-bitinteger exists, you need to return -1. Example 1:...
LeetCode题目:503. Next Greater Element II Given acircular array (the next element of the last element is the first element of the array),print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the...
【Leetcode】556. Next Greater Element III 1 要注意结果,因为可能结果超出32bit能表示的范围了 2 思路是https://leetcode.com/problems/next-greater-element-iii/discuss/101824/Simple-Java-solution-(4ms)-with-explanation.
leetcode 503.下一个更大元素 ii #栈鱼沙 97 播放 · 0 弹幕 【300题刷题挑战】leetcode力扣225 用队列实现栈 mystack 第一百三十九题 | 栈和队列 soulbit花云田 115 播放 · 0 弹幕 leetcode503. next greater element ii 【m】用户正在刷题磕cp 29 播放 · 0 弹幕 【300题刷题挑战...
public int[] nextGreaterElement(int[] findNums, int[] nums) { Map<Integer, Integer> map = new HashMap<>(); // map from x to next greater element of x Stack<Integer> stack = new Stack<>(); for (int num : nums) { //pay attention, we use nums2 to constuact our map, and ...
题目地址:https://leetcode.com/problems/minesweeper/description/ 题目描述 Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first grea...
额外思考:如果目前栈长这个样子:底4->3, 3.5 过来的话,由于 3.5 大于栈顶的3,那么就把3抽掉;然后用3.5和新的栈顶4对比,发现3.5比4小,所以把3.5和4构成一对新的键值;并把3.5压到栈顶。 3 解题代码 ## LeetCode 496fromtypingimportListclassSolution:defnextGreaterElement(self,nums1:List[int],nums2:...