Can you solve this real interview question? Next Greater Element I - The next greater element of some element x in an array is the first greater element that is to the right of x in the same array. You are given two distinct 0-indexed integer arrays num
Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the array, which means you could search ci...
publicint[] nextGreaterElement(int[] findNums,int[] nums) {int[] result =newint[findNums.length];intn=0;for(inti=0; i < findNums.length; i++) {for(intj=0; j < nums.length; j++) {if(nums[j] == findNums[i]) {booleanisFind=false;for(intk=j +1; k < nums.length; k++...
Next Greater Element I? Leetcode 496. Next Greater Element I的时间复杂度是多少? 1. Description 2. Solution **解析:**Version 1,由于元素是唯一的,通过循环找出每个nums2中的满足条件结果保存到字典中,遍历nums1,获得结果。Version 2通过使用栈来寻找满足条件的结果,减少搜索时间。 Version 1 代码语言:...
next-greater-element-I 【描述】:You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1’s elements in the corresponding places of nums2. ...
LeetCode——503. 下一个更大元素 II[Next Greater Element II][中等]——分析及代码[Java] 一、题目 二、分析及代码 1. 单调栈 (1)思路 (2)代码 (3)结果 三、其他 一、题目 给定一个循环数组(最后一个元素的下一个元素是数组的第一个元素),输出每个元素的下一个更大元素。数字 x 的下一个更大...
[leetcode] 503. Next Greater Element II Description Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order...
Find all the next greater numbers for nums1's elements in the corresponding places of nu...leetcode 496. Next Greater Element I ...[LeetCode] 496. Next Greater Element I 题目内容 https://leetcode-cn.com/problems/next-greater-element-i/ 给定两个没有重复元素的数组 nums1 和 nums2 ,...
leetcode556. Next Greater Element III 题目要求 Given a positive32-bitintegern, you need to find the smallest32-bitinteger which has exactly the same digits existing in the integernand is greater in value than n. If no such positive32-bitinteger exists, you need to return -1....
简介:LeetCode之Next Greater Element I 1、题目 You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.The Next Greater Number of a number x in...