For number 1 in the first array, the next greater number for it in the second array is 3. For number 2 in the first array, there is no next greater number for it in the second array, so output -1. Example 2: Input:nums1= [2,4],nums2= [1,2,3,4].Output:[3,-1]Explanation...
publicint[] nextGreaterElement(int[] findNums,int[] nums) {int[] result =newint[findNums.length];intn=0;for(inti=0; i < findNums.length; i++) {for(intj=0; j < nums.length; j++) {if(nums[j] == findNums[i]) {booleanisFind=false;for(intk=j +1; k < nums.length; k++...
需要注意的是 当i>=n时,元素不用入栈,这些元素是为了将之前元素的next greater element找出来的,如果入栈的话,也可能会出现在res里,就不对了。 classSolution {public: vector<int> nextGreaterElements(vector<int>&nums) {intn=nums.size(); vector<int> res(n,-1); stack<int> s;//store indexfor...
class Solution(object): def nextGreaterElement(self,nums1,nums2): stk=[] #单调栈 hashTable={} #哈希表 for i in range(len(nums2)-1,-1,-1): #反向遍历 print(i) cur=nums2[i] while stk!=[] and stk[-1]<=cur: #关键 stk.pop() if stk: hashTable[cur]=stk[-1] else: hashTa...
For number 2 in the first array, the next greater number for it in the second array is 3. For number 4 in the first array, there is no next greater number for it in the second array, so output -1. 给你两个数组,为数组1和数组2,数组1为数组2的子集。找出数组1的每一个元素在数组2中...
For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1. For number 1 in the first array, the next greater number for it in the second array is 3. For number 2 in the first array, there is no next greater number for it...
LeetCode——496. 下一个更大元素 I[Next Greater Element I][简单]——分析及代码[C++] 一、题目 二、分析及代码 1. 单调栈 + 哈希表 (1)思路 (2)代码 (3)结果 三、其他 一、题目 给你两个 没有重复元素 的数组 nums1 和 nums2 ,其中nums1&nbs...Leet...
简介:LeetCode之Next Greater Element I 1、题目 You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.The Next Greater Number of a number x in...
题目地址:https://leetcode.com/problems/self-dividing-numbers/description/ 题目描述 You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1’s elements in the corresponding places of nums2. ...
1 读题:LeetCode 496E 下一个最大元素 2 解题思路 单调栈(栈底最大)的作用在于: 保持栈底始终是一个全栈最大的数值; 目标原来过来,和栈顶的元素对比 (此时要求栈非空),如果栈顶的元素比它大,那么就找到了一个离它最近的、且比它大的元素;