503. Next Greater Element II # 题目 # Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to
publicint[]nextGreaterElement(int[] nums1,int[] nums2){int[] result =newint[nums1.length];for(inti=0; i<nums1.length; i++) {intj =0, k =0;for(; j<nums2.length; j++) {if(nums1[i] == nums2[j]) {break; } }for(k = j+1; k<nums2.length; k++) {if(nums2[k] >...
解法: classSolution{public:vector<int>nextGreaterElement(vector<int>& findNums, vector<int>& nums){intsz = nums.size();vector<int>greater(sz,-1);for(inti = sz-2; i >=0; i--){intidx = i+1;while(idx !=-1&& nums[idx] < nums[i]){ idx = greater[idx]; } greater[i] = i...
Explanation:For number 2 in the first array, the next greater number for it in the second array is 3. For number 4 in the first array, there is no next greater number for it in the second array, so output -1. question 解法: 小伙伴的思路更加简单,时间复杂度O(n),leetcode上击败98% ...
def nextGreaterElement(self,nums1,nums2): stk=[] #单调栈 hashTable={} #哈希表 for i in range(len(nums2)-1,-1,-1): #反向遍历 print(i) cur=nums2[i] while stk!=[] and stk[-1]<=cur: #关键 stk.pop() if stk: hashTable[cur]=stk[-1] ...
For number 1 in the first array, the next greater number for it in the second array is 3. For number 2 in the first array, there is no next greater number for it in the second array, so output -1. 1. 2. 3. 4. 5. 6. ...
LeetCode题目:496. Next Greater Element I You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2. ...
Leetcode496. Next Greater Element I 这个题,开始我是想用find和upper_bound两个函数解决,但是 upper_bound并不对。 upper_bound返回的是插入的数字的上界。 如一个数组number序列1,2,2,4.upper_bound(2)后,返回的位置是3(下标)也就是4所在的位置。
简介:LeetCode之Next Greater Element I 1、题目 You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.The Next Greater Number of a number x in...
For number 2 in the first array, the next greater number for it in the second array is 3. For number 4 in the first array, there is no next greater number for it in the second array, so output -1. 给你两个数组,为数组1和数组2,数组1为数组2的子集。找出数组1的每一个元素在数组2中...