Next Greater Element I ...[LeetCode] 496. Next Greater Element I 题目内容 https://leetcode-cn.com/problems/next-greater-element-i/ 给定两个没有重复元素的数组 nums1 和 nums2 ,其中nums1 是 nums2 的子集。找到 nums1 中每个元素在 nums2 中的下一个比其大的值。 ......
publicint[] nextGreaterElement(int[] findNums,int[] nums) {int[] result =newint[findNums.length];intn=0;for(inti=0; i < findNums.length; i++) {for(intj=0; j < nums.length; j++) {if(nums[j] == findNums[i]) {booleanisFind=false;for(intk=j +1; k < nums.length; k++...
需要注意的是 当i>=n时,元素不用入栈,这些元素是为了将之前元素的next greater element找出来的,如果入栈的话,也可能会出现在res里,就不对了。 classSolution {public: vector<int> nextGreaterElements(vector<int>&nums) {intn=nums.size(); vector<int> res(n,-1); stack<int> s;//store indexfor...
Can you solve this real interview question? Next Greater Element I - The next greater element of some element x in an array is the first greater element that is to the right of x in the same array. You are given two distinct 0-indexed integer arrays num
下一个更大元素 I(Next Greater Element I) 技术标签: LeetCode刷题LeetCode下一个更大元素 I 给定两个没有重复元素的数组 nums1 和 nums2 ,其中nums1 是 nums2 的子集。找到 nums1 中每个元素在 nums2 中的下一个比其大的值。nums1 中数字 x 的下一个更大元素是指 x 在 nums2 中对应位置的右边...
def nextGreaterElement(self,nums1,nums2): stk=[] #单调栈 hashTable={} #哈希表 for i in range(len(nums2)-1,-1,-1): #反向遍历 print(i) cur=nums2[i] while stk!=[] and stk[-1]<=cur: #关键 stk.pop() if stk: hashTable[cur]=stk[-1] ...
【链接】:next-greater-element-I 【描述】:You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1’s elements in the corresponding places of nums2. ...
简介:LeetCode之Next Greater Element I 1、题目 You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.The Next Greater Number of a number x in...
https://leetcode.com/problems/next-greater-element-i/#/description 题目: You are given two arrays (without duplicates)nums1andnums2wherenums1’s elements are subset ofnums2. Find all the next greater numbers fornums1's elements in the corresponding places ofnums2. ...
For number 2 in the first array, the next greater number for it in the second array is 3. For number 4 in the first array, there is no next greater number for it in the second array, so output -1. 给你两个数组,为数组1和数组2,数组1为数组2的子集。找出数组1的每一个元素在数组2中...