pre= root->val; inorder(root->right, pre, res); } }; 其实我们也不必非要用中序遍历不可,用先序遍历同样可以利用到BST的性质,我们带两个变量low和high来分别表示上下界,初始化为int的极值,然后我们在递归函数中,分别用上下界和当前节点值的绝对差来更新结果res,参见代码如下: 解法二: classSolution {p...
回到顶部 非BST的解法 代码源自LeetCode讨论区。利用了java的排序树。 publicclassSolution{ TreeSet<Integer> set =newTreeSet<>();intmin=Integer.MAX_VALUE;publicintgetMinimumDifference(TreeNode root){if(root ==null)returnmin;if(!set.isEmpty()) {if(set.floor(root.val) !=null) { min = Math....
return nodes[0] diff_nodes = [nodes[i+1] - nodes[i] for i in range(len(nodes)) if i + 1 < len(nodes)] for item in diff_nodes: if item < minValue: minValue = item return minValue 还有一个奇葩的问题,783.Minimum Distance Between BST Nodes, 题的代码,和530题代码, 方法内部全部...
public class Solution { int minDiff = Integer.MAX_VALUE; TreeNode prev = null; public int getMinimumDifference(TreeNode root) { inOrder(root); return minDiff; } public void inOrder(TreeNode root){ if(root == null){ return; } inOrder(root.left); if(prev !=null) minDiff= Math.min...
Thanks in Advance. One of Discussions:https://leetcode.com/problems/minimum-distance-between-bst-nodes/discuss/856052/My-Java-SOlution-DFS/705372Problem Link:https://leetcode.com/problems/minimum-distance-between-bst-nodes/ #dfs,bst,difference...
Leetcode 783: Minimum Distance Between BST Nodes 问题描述: Given the root of a Binary Search Tree (BST), return the minimum difference between the values of any two different nodes in the tree. 找出二叉搜索树中两个节点的最小差值 思路: 既然是二叉搜索树,则中序遍历可以获得升序排列的一组数...
【Leetcode_easy】783. Minimum Distance Between BST Nodes,problem783. MinimumDistanceBetweenBSTNodes参考1.Leetcode_easy_783. MinimumDistanceBetweenBSTNodes;完
The BST is always valid, each node’s value is an integer, and each node’s value is different. 思路: BST + 中序,再求minimum difference 代码如下: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 public int minDiffInBST(TreeNode root) { vis = new ArrayList<Integer>(); dfs(root);...
The BST is always valid, each node's value is an integer, and each node's value is different. 1 2 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} ...
LeetCode 题目 153. Find Minimum in Rotated Sorted Array 涉及到在特定条件下寻找最小值的策略。 思考方法: 遍历可能的前缀长度 k。 检查前缀 s[:k] 是否能在当前位置复制。 记录并更新最小操作次数。 Python 代码s=input#读取目标字符串 n=len(s)#计算字符串长度 ...