[LeetCode]Find Median from Data Stream Find Median from Data Stream Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4], the median is3 [2,3], ...
题目地址:https://leetcode.com/problems/sliding-window-median/ 题目描述 Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4], the median is3 [2,3]...
题目地址:https://leetcode.com/problems/sliding-window-median/ 题目描述 Median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value. So the median is the mean of the two middle value. Examples: [2,3,4], the median is3 [2,3]...
/** @lc app=leetcodeid=295 lang=cpp** [295] Find Median from Data Stream** https://leetcode.com/problems/find-median-from-data-stream/description/** algorithms* Hard (38.20%)* Likes: 1380* Dislikes: 27* Total Accepted: 125K* Total Submissions: 326.7K* Testcase Example: '["MedianFi...
/** @lc app=leetcode id=480 lang=cpp** [480] Sliding Window Median** https://leetcode.com/problems/sliding-window-median/description/**algorithms* Hard (33.54%)* Likes: 510* Dislikes: 53* Total Accepted: 31.8K* Total Submissions: 93.8K* Testcase Example: '[1,3,-1,-3,5,3,6,7...
There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 1publicclassSolution {2publicdoublefindMedianSortedArrays(intA[],intB[]) {3intalen =A.length;4intblen =B.length;5if...
leetcode two heap use two heap is quite straight forward. importjava.util.Comparator;importjava.util.PriorityQueue;publicclassMedianFinder{PriorityQueue<Integer>left;PriorityQueue<Integer>right;MedianFinder(){left=newPriorityQueue<>(10,newComparator<Integer>(){@Overridepublicintcompare(Integero1,Integero2)...
Solution 2 -- Balanced BST 平衡二叉树也可以满足条件,但是实际代码太多。所以可以在面试时优先用heap写出代码,然后follow-up的时候提出平衡二叉树的思想。
代码的话,我们首先定义一个二分查找树。和普通的二分查找树不同的地方在于,节点多了一个成员变量,记录以当前节点为根节点的二叉树的总节点数量。 此外实现了find函数,来返回有序情况下第k个节点的值。 classBST{classNode{intval;intsize;Nodeleft,right;Node(intv){...