1 class Solution { 2 public: 3 //reference: http://www.cnblogs.com/remlostime/archive/2012/11/16/2774077.html 4 string minWindow(string S, string T) {
leetcode--Minimum Window Substring 1.题目描述 Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example, S = "ADOBECODEBANC" T = "ABC" Minimum window is "BANC". Note: If there is no such window in...
func minWindow(s string, t string) string { m := len(s) // count[ch] 表示滑动窗口 [l, r) 中字母 ch 还需出现的次数 count := make(map[byte]int) // 初始化为 t 中每个字母的出现次数 for _, ch := range t { count[byte(ch)] += 1 } // remain 表示滑动窗口 [l, r) 中还...
LeetCode 76_Minimum Window Substring https://leetcode.cn/problems/minimum-window-substring/ 一、个人版本 public class Solution1 { public String minWindow(String s, String t) { Balance balance = new Balance(s, t); Integer[] idxList = balance.idxList; if (idxList.length == 0 || idxList...
题目链接:https://leetcode.com/problems/minimum-window-substring/ 题目: Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n). For example, S ="ADOBECODEBANC" ...
Minimum Window Substring@LeetCode Minimum Window Substring 典型的窗口操作题,维护两个哈希表,stdMap标准表,map当前表,标准表用来保存T中的字符信息,当前表用来保存当前窗口的字符信息。 对窗口的操作包括以下两个: 扩充窗口:将窗口的右端点尽力向右扩展,直至到包含所有标准表中的字符(窗口中的每个有效字符的数量...
Can you solve this real interview question? Minimum Window Substring - Given two strings s and t of lengths m and n respectively, return the minimum window substring of s such that every character in t (including duplicates) is included in the window. If
S="ADOBECODEBANC" T="ABC" Minimum window is"BANC". Note: If there is no such window in S that covers all characters in T, return the emtpy string"". If there are multiple such windows, you are guaranteed that there will always be only one unique minimum window in S. ...
Minimum Window Substring 欢迎访问原文所在博客:https://52heartz.top/articles/leetcode-76-minimum-window-substring/ 解答1[Java]: 思路 注意 if (map[s.charAt(right++)]-- > 0) 这句,不论 right 指向位置的字符是哪个,在判断之后都会被减去 1。因为在前边的语句中,已经预先把 t 中的字符在 map 中...
输入:s = "ADOBECODEBANC", t = "ABC" 输出:"BANC" 解释:最小覆盖子串 "BANC" 包含来自字符串 t 的 'A'、'B' 和 'C'。 示例2: 输入:s = "a", t = "a" 输出:"a" 解释:整个字符串 s 是最小覆盖子串。 示例3: 输入: s = "a", t = "aa" 输出: "" 解释: t 中两个字符 '...