此解法的时间复杂度是O(N),最坏情况下时间复杂度是O(N^2),因为HashSet的contains方法;空间复杂度是O(N)。 publicintlengthOfLongestSubstring3(String s){ Set<Character> set =newHashSet<Character>();intn=s.length(), left =0, right =0;intresult=0;while(left < n && right < n) {if(!set...
笔者在完成LeetCode第三题(Longest Substring Without Repeating Characters)时,经历了设计、实现、优化三个阶段,于是通过这个三部曲系列,将当初的整个过程重现,希望有兴趣的读者来一起讨论; 三部曲完整链接 《LeetCode第三题(Longest Substring Without Repeating Characters)三部曲之一:解题思路》; 《LeetCode第三题(Lon...
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest substring is "b", with the length of 1. 解法一:枚举出字符串的所有...
intlengthOfLongestSubstring(string s){map<char,int>resultMap;int head=0,tail=0;int maxLen=0;while(tail<s.length()){map<char,int>::iterator iter=resultMap.find(s[tail]);if(iter!=resultMap.end()){if((tail-head)>maxLen)maxLen=tail-head;int index=iter->second;for(int i=head;i<=in...
Given a string, find the length of thelongest substringwithout repeating characters. Example 1: Input:"abcabcbb"Output:3Explanation:The answer is"abc", with the length of 3. Example 2: Input:"bbbbb"Output:1Explanation:The answer is"b", with the length of 1. ...
LeetCode 3.Longest Substring Without Repeating-4.Median of Two Sorted Arrays. Characters 3. 无重复字符的最长子串 方法一:滑动窗口 class Solution: def lengthOfLongestSubstring(self, s: str) -> int: d = {} # element:index ,element的位置...
Given a string, find the length of the longest substring without repeating characters. Examples: Given “abcabcbb”, the answer is “abc”, which the length is 3. Given “bbbbb”, the answer is “b”, with the length of 1. Given “pwwkew”, the answer is “wke”, with the length...
Can you solve this real interview question? Longest Substring Without Repeating Characters - Given a string s, find the length of the longest substring without duplicate characters. Example 1: Input: s = "abcabcbb" Output: 3 Explanation: The answer
无重复字符的最长子串 - LeetCode (中国)leetcode-cn.com/problems/longest-substring-without-repeating-characters 方法一、暴力法: 思路 逐个检查所有的子字符串,看它是否不含有重复的字符。 算法 假设我们有一个函数 boolean allUnique(String substring) ,如果子字符串中的字符都是唯一的,它会返回true,否则...
Can you solve this real interview question? Longest Substring Without Repeating Characters - Given a string s, find the length of the longest substring without duplicate characters. Example 1: Input: s = "abcabcbb" Output: 3 Explanation: The answer