It can be shown that all other substrings contain either "aaa" or "cb" as a substring. Example 2: Input: word = "leetcode", forbidden = ["de","le","e"] Output: 4 Explanation: There are 11 valid substrings in word: "l", "t", "c", "o", "d", "tc", "co", "od", ...
public class Solution { /** * @param s: input string * @return: the longest palindromic substring */ public String longestPalindrome(String s) { // write your code here char[] S = s.toCharArray(); int sLength = S.length; String[][] f = new String[sLength ][sLength ]; return ...
5. Longest Palindromic Substring Given a strings, returnthe longestpalindromicsubstringins. Example 1: Input:s = "babad"Output:"bab"Explanation:"aba" is also a valid answer. Example 2: Input:s = "cbbd"Output:"bb" Constraints: 1 <= s.length <= 1000...
41. Longest Valid Parentheses 最长有效括号算法:本题用两种方法解,一是stack,二是双向遍历面试准备系列,注重培养互联网大厂的面试能力,注重编程思路,coding限时,代码规范,想要求职,转行或者跳槽的朋友们别忘了一键三连一下,新人up主需要你宝贵的支持哟~
Given “pwwkew”, the answer is “wke”, with the length of 3. Note that the answer must be a substring, “pwke” is a subsequence and not a substring. 题意就不说了,这道题是求的是最大的不重复的子串,求解重复子串可以类似采用最长公共子串的解法。
Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example: AI检测代码解析 Input: "babad" Output: "bab" Note: "aba" is also a valid answer. 1. 2. 3. 4.
stack.empty()&&stack.peek()=='('){stack.pop();}else{returnfalse;}}returnstack.empty();}publicintlongestValidParentheses(Strings){intmaxlen=0;for(inti=0;i<s.length();i++){for(intj=i+2;j<=s.length();j+=2){if(isValid(s.substring(i,j))){maxlen=Math.max(maxlen,j-i);}}}...
classSolution{public StringlongestPalindrome(String s){//从长到短截取所有子字符串String sub="";int count;boolean tag=false;for(int i=s.length();i>0;i--){//i 子字符串长度for(int j=0;j<=s.length()-i;j++){//j 子字符串起始位置sub=s.substring(j,j+i);//判断是否是回文count=0;...
原文链接:LeetCode Top 100 高频算法题 05:Longest Palindromic Substring LeetCode Top 100高频算法题,即LeetCode上最高频的100道求职面试算法题。小编和实验室同学之前面试找工作,也只刷了剑指offer和这top 100算法题,在实际面试中也遇到了很多LeetCode上的原题。剑指offer算法最优解之前和大家分享了,LeetCode Top...
LeetCode:32. Longest Valid Parentheses(最长的有效匹配串) Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring. Example 1: 方法1: 时间复杂度:O(n^2) 空间复杂度:O(n)......