输入:s = "ADOBECODEBANC", t = "ABC" 输出:"BANC" 解释:最小覆盖子串 "BANC" 包含来自字符串 t 的 'A'、'B' 和 'C'。 示例2: 输入:s = "a", t = "a" 输出:"a" 解释:整个字符串 s 是最小覆盖子串。 示例3: 输入: s = "a", t = "aa" 输出: "" 解释: t 中两个字符 '...
分类: coding, leetcode 标签: coding, leetcode, DP 好文要顶 关注我 收藏该文 微信分享 zhanzq1 粉丝- 1 关注- 0 +加关注 0 0 « 上一篇: leetcode 1016. 子串能表示从 1 到 N 数字的二进制串(Binary String With Substrings Representing 1 To N) » 下一篇: leetcode 313. 超级丑...
1publicclassSolution {2publicString minWindow(String s, String t) {3if(s ==null|| t ==null|| s.length() <t.length()){4return"";5}67int[] map =newint[256];8for(charc : t.toCharArray()){9map[c]++;10}1112intcount =t.length();13intminLen =Integer.MAX_VALUE;14inthead = ...
On each step we choose one of substrings "ab" in the string and replace it with the string "bba&qu...[Array]Minimum Size Subarray Sum Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn’t ...
链接:https://leetcode-cn.com/problems/minimum-remove-to-make-valid-parentheses 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 思路是stack但是这个题跟20题valid parenthesis还不太一样,因为不光是判断,而是最后需要返回一个有效的结果。这个题我没有用到stack但是用到了stack的思想,用...
* 1. finding out the longest sub-array sum up to nums.sum-x, * 2. the result is nums.size - sub-array.size, **/fun minOperations(nums: IntArray, x: Int): Int { val target= nums.sum() -x var lengthOfSubArray=Int.MIN_VALUE ...
tank += -heapq.heappop(que) res +=1iftank <0:return-1heapq.heappush(que, -g) prev = preturnres 参考资料:https://leetcode.com/problems/minimum-number-of-refueling-stops/solution/ 日期 2019 年 4 月 3 日—— 好久不刷题了,越来越手生...
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"bcde" is the answer because it occurs before "bdde" which has the same length. "deb" is not a smaller window because the elements of T in the window must occur in order. Note: All the strings in the input will only contain lowercase letters. ...