maxVal : minVal;//根据三个点的值缩小搜索范围if(midVal >maxVal)returnfindMinVal((min + max) /2, max, rotateArray);elseif(minVal >midVal)returnfindMinVal(min, (min + max) /2, rotateArray);//先无视这个return先,等等再讨论returnminVal; } 考虑特殊情况 如果我们放上Leetcode提交,这肯定是过...
用旋转的情况假设第一个小于最后一个那么最小值肯定也是第一个,也就是说计算过程中只要找到left<right的结果就出来了 2、如果这里面出现了rotate的话,如【3,4,1,2】那么最小值肯定会出现在左右的一遍,那么到底是哪边呢,这里我们可以比较最左和最后值的大小,比如这里`3="">2说明在这里前面的那个3是旋转过去...
LeetCode: 154. Find Minimum in Rotated Sorted Array II 题目描述 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum ...
Find Minimum in Rotated Sorted Array II Total Accepted:25678Total Submissions:80978My Submissions QuestionSolution Follow upfor "Find Minimum in Rotated Sorted Array": What ifduplicatesare allowed? Would this affect the run-time complexity? How and why? Suppose a sorted array is rotated at some...
Can you solve this real interview question? Find Minimum in Rotated Sorted Array - Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: * [4,5,6,7,0,1,2] if
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和Find Minimum in Rotated Sorted Array 题目类似 如果 数组中有重复元素怎么办 这会影响运行的时间复杂度吗 假设一个按升序排序的数组在你事先未知的某个旋转点旋转。 (例如: 0 1 2 4 5 6 7 可能变成 4 5 6 7 0 1 2)。 找到数组中最小的元素。
Contributor:LeetCode Follow upfor "Find Minimum in Rotated Sorted Array": **What ifduplicatesare allowed? Would this affect the run-time complexity? How and why? ** Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. ...
1. 无重复 Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 思路:这个是找最小,和找指定数字其实差不多的。画个示意图吧 ...
https://oj.leetcode.com/problems/find-minimum-in-rotated-sorted-array-ii/ 允许重复,也就意味着会有a[l]==a[r],以及a[mid]==a[r]的情况出现。后者比较好办,从坐标图中看出直接r=mid即可。 前者会有一个问题是当a[mid]==a[r]时,无法确定这个中间值在折线上的位置,此时退化为线性搜索,令l++。