1. 无重复 Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 思路:这个是找最小,和找指定数字其实差不多的。画个示意图吧 二分...
3.如果中间值小于左边的值,那么最小值不是中间的值就是在左边一块了。 classSolution {public:intfindMin(vector<int> &num) {intlen = num.size(), left =0, right = len -1, mid = (left + right ) /2, minmum =INT_MAX;while(left !=right) { mid= (left + right) /2;if(num[mid] ...
public int findMin(int[] nums) { int start = 0; int end = nums.length - 1; while (start < end) { int mid = (start + end) >>> 1; if (nums[mid] > nums[end]) { start = mid + 1; } else { end = mid; } } return nums[start]; } 解法二 解法一中我们把 mid 和end ...
Find the minimum element. The array may contain duplicates. Example 1: Input: [1,3,5] Output: 1 Example 2: Input: [2,2,2,0,1] Output: 0 Note: This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why?
【Leetcode】Find Minimum in Rotated Sorted Array 题目链接:https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/ 题目: Suppose a sorted array is rotated at some pivot unknown to you beforehand. 0 1 2 4 5 6 7might become4 5 6 7 0 1 2)....
LeetCode: 154. Find Minimum in Rotated Sorted Array II 题目描述 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). ...
Can you solve this real interview question? Find Minimum in Rotated Sorted Array - Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: * [4,5,6,7,0,1,2] if
Given the sorted rotated array nums of unique elements, return the minimum element of this array. You must write an algorithm that runs in O(log n) time. <a href="https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/description/" target="_blank">Leetcode Link</a> ...
findMinimuminRotatedSortedArrayII(){varnums1=[Int]()nums1=[2,2,2,1,1,1,1,1,1]print(Solution().findMin(nums1))print(nums1)}
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 二分迭代法 复杂度 ...