Given the head of a singly linked list, return the middle node of the linked list.If there are two middle nodes, return the second middle node. 英文版地址 leetcode.com/problems/m 中文版描述 给定一个头结点为 head 的非空单链表,返回链表的中间结点。如果有两个中间结点,则返回第二个中间结点。
01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第206题(顺位题号是876)。给定具有头节点的非空单链表,返回链表的中间节点。如果有两个中间节点,则返回第二个中间节点。例如: 输入:[1,2,3,4,5] 输出:此列表中的节点3(序列化:[3,4,5]) 返回的节点的值为3.(该节点的判断序列化为[3,4,5])。
merge left, right的程序可以参考[LeetCode] 21. Merge Two Sorted Lists_Easy tag: Linked List。 code #Definition for singly-linked list.#class ListNode:#def __init__(self, x):#self.val = x#self.next = NoneclassSolution:deffindMiddle(self, head):slow, fast=head, headwhilefast:iffast.ne...
代码(Go) /** * Definition for singly-linked list. * type ListNode struct { * Val int * Next *ListNode * } */ func middleNode(head *ListNode) *ListNode { // 初始化快慢指针均为头结点 fast := head slow := head // 如果快指针还能走两步,则继续循环 for fast != nil && fast.Next...
思路 先全部塞入数组,再根据长度/2得到中间元素的下标,再返回。 最终代码 <?php /** * Definition for a singly-linked list. * class ListNode { * public $val = 0; * public $next = null; * function __construct($val) { $this->val = $val; } ...
package leetcode /** * Definition for singly-linked list. * type ListNode struct { * Val int * Next *ListNode * } */ func middleNode(head *ListNode) *ListNode { if head == nil || head.Next == nil { return head } p1 := head p2 := head for p2.Next != nil && p2.Next....
876. 链表的中间结点 - 给你单链表的头结点 head ,请你找出并返回链表的中间结点。 如果有两个中间结点,则返回第二个中间结点。 示例 1: [https://assets.leetcode.com/uploads/2021/07/23/lc-midlist1.jpg] 输入:head = [1,2,3,4,5] 输出:[3,4,5] 解释:链表
leetcode刷题--Middle of the Linked List 1. 题目描述 Given a non-empty, singly linked list with head node head, return a middle node of linked list. If there are two middle nodes, return the second middle node. 2. 示例 3. 算法思路 思路一:统计链表的长度,然后遍历找到中间......
一、问题描述 Given a non-empty, singly linked list with head node head, return a middle node of linked list. If there are two middle nodes, return the second middle node. Example: Input: [1,2,3,4,5] Output: Node 3 from this list (Serialization: [3,4,5]) ...
LeetCode 0876. Middle of the Linked List链表的中间结点【Easy】【Python】【双指针】 Problem LeetCode Given a non-empty, singly linked list with head nodehead, return a middle node of linked list. If there are two middle nodes, return the second middle node. ...