}publicListNode sortList(ListNode head) {if(head ==null|| head.next ==null){returnhead; } ListNode middleNode=getMiddleNode(head); ListNode nextNode=middleNode.next; middleNode.next=null;returnmergeList(sortList(head), sortList(nextNode)); }publicstaticvoidmain(String[] args){int[] arr ...
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to the next node of ...
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