* Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */classSolution{publicListNodemiddleNode(ListNode head){ListNodefast=head, slow = head;while(fast !=null&& fast.next !=null) { slow = slow.next; fast ...
Given the head of a singly linked list, return the middle node of the linked list.If there are two middle nodes, return the second middle node. 英文版地址 leetcode.com/problems/m 中文版描述 给定一个头结点为 head 的非空单链表,返回链表的中间结点。如果有两个中间结点,则返回第二个中间结点。
代码(Go) /** * Definition for singly-linked list. * type ListNode struct { * Val int * Next *ListNode * } */ func middleNode(head *ListNode) *ListNode { // 初始化快慢指针均为头结点 fast := head slow := head // 如果快指针还能走两步,则继续循环 for fast != nil && fast.Next...
If there are two middle nodes, return the second middle node. Example 1: Input:[1,2,3,4,5]Output:Node3fromthis list (Serialization: [3,4,5]) The returned node has value3. (The judge's serialization of this node is [3,4,5]).Note that we returned a ListNodeobjectans, such that...
876. Middle of the Linked List 题目分析 返回一个链表中最中间的元素。 思路 先全部塞入数组,再根据长度/2得到中间元素的下标,再返回。 最终代码 <?php /** * Definition for a singly-linked list. * class ListNode { * public $val = 0; ...
// 链表的中间结点(LeetCode 876):https://leetcode.cn/problems/middle-of-the-linked-list/ classSolution{ publicListNodemiddleNode(ListNode head){ // 设置两个指针,一开始都指向链表的头节点 ListNode slow = head; ListNode fast = head; // 接下来,让这两个指针向前移动 ...
给你单链表的头结点head,请你找出并返回链表的中间结点。 如果有两个中间结点,则返回第二个中间结点。 示例1: 输入:head = [1,2,3,4,5]输出:[3,4,5]解释:链表只有一个中间结点,值为 3 。 示例2: 输入:head = [1,2,3,4,5,6]输出:[4,5,6]解释:该链表有两个中间结点,值分别为 3 和 4 ...
0876 Middle of the Linked List LeetCode 力扣 Python CSDN Easy 双指针 0892 Surface Area of 3D Shapes LeetCode 力扣 Python CSDN Easy 数学 0914 X of a Kind in a Deck of Cards LeetCode 力扣 Python CSDN Easy 数学 0994 Rotting Oranges LeetCode 力扣 Python CSDN Easy BFS 1013 Partition Array ...
876 Middle of the Linked List Easy Go 897 Increasing Order Search Tree Easy 905 Sort Array By Parity Easy Go 917 Reverse Only Letters Easy Go 922 Sort Array By Parity II Easy Go 925 Long Pressed Name Easy Go 933 Number of Recent Calls Easy 942 DI String Match Easy Go 977 Squares ...
struct ListNode*middleNode(struct ListNode*head){struct ListNode*slower=head;struct ListNode*faster=head;//注意边界条件while((faster!=NULL)&&(faster->next!=NULL)){faster=faster->next->next;slower=slower->next;}returnslower;} 328. 奇偶链表 ...