Given the head of a singly linked list, return the middle node of the linked list.If there are two middle nodes, return the second middle node. 英文版地址 leetcode.com/problems/m 中文版描述 给定一个头结点为 head 的非空单链表,返回链表的中间结点。如果有两个中间结点,则返回第二个中间结点。
If there are two middle nodes, return the second middle node. Example 1: Input:[1,2,3,4,5]Output:Node3fromthis list (Serialization: [3,4,5]) The returned node has value3. (The judge's serialization of this node is [3,4,5]).Note that we returned a ListNodeobjectans, such that...
Given a non-empty, singly linked list with head node head, return a middle node of linked list. If there are two middle nodes, return the second middle node. Example 1: Input:[1,2,3,4,5]Output:Node3fromthis list (Serialization: [3,4,5]) The returned node has value3. (The judge...
1 <= Node.val <= 10 ^ 5 样例 思路:快慢指针/双指针 本题是 LeetCode 876 - 链表的中间结点 和LeetCode 203 - 移除链表元素 的加强版,数据范围加大,并需要删除中间结点。 对于链表的题目,一般都可以使用一个哨兵结点。 本题使用哨兵结点,方便处理删除头结点这种边界情况。 因为本题需要删除中间结点,所以...
最终代码 <?php /** * Definition for a singly-linked list. * class ListNode { * public $val = 0; * public $next = null; * function __construct($val) { $this->val = $val; } * } */ class Solution { function middleNode($head) { ...
示例2: 输入:head = [1,2,3,4,5,6]输出:[4,5,6]解释:该链表有两个中间结点,值分别为 3 和 4 ,返回第二个结点。 提示: 链表的结点数范围是[1, 100] 1 <= Node.val <= 100 © 2025 领扣网络(上海)有限公司
Given a non-empty, singly linked list with head node head, return a middle node of linked list. If there are two middle nodes, return the second middle node. Example: Input: [1,2,3,4,5] Output: Node 3 from this list (Serialization: [3,4,5]) ...
LeetCode Given a non-empty, singly linked list with head nodehead, return a middle node of linked list. If there are two middle nodes, return the second middle node. Example 1: Input:[1,2,3,4,5]Output:Node3from thislist(Serialization:[3,4,5])The returned node has value3.(The jud...
File metadata and controls Code Blame 69 lines (58 loc) · 1.35 KB· Raw #include <stdio.h> #include <stdlib.h> /* Link list node */ struct Node { int data; struct Node *next; }; /* Function to get the middle of the linked list*/ void printMiddle(struct Node *head) { str...
1 <= Node.val <= 100IdeaUse two pointers. Slow pointer advance one node at a time, while fast pointer advances two n Two Pointers Linked List ide 转载 mb5fe559619e363 2021-08-08 12:04:00 61阅读 2评论 【leetcode】Permutations (middle) Given a collection of numbers, return all ...