Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 两个排好序的链表拼接,只要用两个指针遍历链表即可. 可以借助一个helper指针来进行开头的合并。如果有一个遍历完,则直接把另一个链表指针之后的部分全部接...
1/**2* Definition for singly-linked list.3* struct ListNode {4* int val;5* ListNode *next;6* ListNode(int x) : val(x), next(NULL) {}7* };8*/910structhelper {11ListNode *head;12intlen;13helper(ListNode *h,intl) : head ( h ), len ( l ) {}14};1516classhelpercmp {17pub...
Here's a list of 30 coding interview patterns, each with one or two example LeetCode problems:1. Sliding WindowProblem 1: Minimum Size Subarray Sum Problem 2: Longest Substring Without Repeating Characters2. Two PointersProblem 1: 3Sum Problem 2: Container With Most Water...
解决一开始获取前驱结点的困难pre=ans# Construct heapforiinrange(len(lists)):# Consider []iflists[i]:heapq.heappush(heap,(lists[i].val,i))whilelen(heap)>0:# The smallest numbersmallest_num,list_index=heapq.heappop(heap)pre.next=ListNode(smallest...
Mergeksorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路I: 选择排序 每次都比较各个list的头指针所指的val,取最小的那个。时间复杂度O(n*k) classSolution {public: ListNode*mergeKLists(vector &lists) {if(lists.empty())returnNULL; ...
野原新之助0 Q: Given an array of integers, sort the elements in the array in ascending order. The merge sort algorithm should be used to solve this problem. 1publicclassSolution {2publicint[] mergeSort(int[] array) {3//Write your solution here4if(array ==null|| array.length == 0...